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3 years ago

N Identify the next (3) numbers in the set: 6, 36, 2, 4, -30... *

Mathematics

2 answers:

sveticcg [70]3 years ago

8 0

Answer:

-60, -120, -154

Step-by-step explanation:

-60, -120, -154

because

from 6 to get to 36, it is multiplied by itself.

from 36 to get to 2, it is subtracted by 34.

the pattern continues.

Can I get brainliest please? Thanks! Hope this helps!

Rainbow [258]3 years ago

8 0

Answer:

900, 866, 749956

Step-by-step explanation:

6*6=36

36-34=2

2*2=4

4-34= -30

-30*-30=900

900-34=866

866*866=749956

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A ladder is leaning against the side of a building and positioned such that the base of the ladder is 17 ft from the base of the

andrezito [222]

Answer:

The ladder is 28.6 feet long.

Step-by-step explanation:

Given that:

Length of base = 17 feet

Length above the ground = 23 feet

These forms two legs of right angled triangle.

The length of ladder will be the hypotenuse.

Using Pythagorean theorem;

$a^2+b^2=c^2\\(17)^2 + (23)^2 = c^2 \\289 + 529 = c^2 \\c^2 = 818$

Taking square root on both sides

$\sqrt{c^2}=\sqrt{818}\\c=28.6$

Hence,

The ladder is 28.6 feet long.

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3 years ago

5000 principal earning 4% compounded annually, 7 years

almond37 [142]

Answer:

Step-by-step explanation:

Basically, you want to know interest. I = prt is the formula. 'I' will be left blank b/c that's unknown. P is principal, 5000. R is rate, 4%, or 0.04 when turned into a decimal. T is time, 7 years. So now when using the formula, it will all become I = 5000(0.04)(7). What that means is you first multiply 5,000 by 0.04, getting 200. Then when you multiply 200 by 7, it's 1,400, which will leave you with I = 1,400. Interest is 1,400.

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2 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

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= (0.13)(0.16) = 0.0208

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$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)