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Vadim26 [7]
3 years ago
15

Estimate the quotient: 1628 ÷ 8 answer choices 168 162 160 260 106

Mathematics
1 answer:
slega [8]3 years ago
5 0

Answer:

203.5 so you can pick 168 because it's closer to the answer

Step-by-step explanation:

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Can I get help on this please
Misha Larkins [42]

Answer:

5. You can round question a up to 100 + 55 (then do the counting)

5. You can round question b up to 245 - 100 (then do the counting)

You can round question c up to 100 x 5 (then do the counting)

You can round question d up to 100 x 20 (then subtract accordingly)

Please rank Brainliest if this helps!

4 0
3 years ago
How to do that? (Indices)<br><br> a<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \frac
Tamiku [17]
\bf a\cdot \cfrac{1}{2}\left(a+\cfrac{1}{a}  \right)\impliedby \textit{let's distribute first}&#10;\\\\\\&#10;\cfrac{a}{2}\left(a+\cfrac{1}{a}  \right)\implies \cfrac{a}{2}\cdot a+\cfrac{\underline{a}}{2}\cdot \cfrac{1}{\underline{a}}\implies \cfrac{a^2}{2}+\cfrac{1}{2}\implies \cfrac{a^2+1}{2}
3 0
3 years ago
Tanner collected 360 cans and bottles while fundraising for the baseball team this was 40% of what Ricky collected how many cans
vekshin1

Answer:

the answer 504

Explanation:

360*0.40=144

so they said 40% reggie collected main mor than 40% collected so you need to do add like 360+144=504

6 0
3 years ago
A 10.0 kg and a 2.0 kg cart approach each other on a horizontal frictionless air track. Their
Flura [38]

the  final speed in m/s of the 10.0 kg is 2.53 m/s .

<u>Step-by-step explanation:</u>

Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their  total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the  final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:

We know that in an elastic collision :

⇒ Total kinetic energy before collision  = Total kinetic energy after collision

⇒ 96 = \frac{1}{2}M_1(v_1)^2 + \frac{1}{2}M_2(v_2)^2

⇒ 96 = \frac{1}{2}(10)(v_1)^2 + \frac{1}{2}(2)(8)^2

⇒ 96=5(v_1)^2 + 64

⇒ 5(v_1)^2  =32

⇒ (v_1)^2  =6.4

⇒ v_1  =2.53 m/s

Therefore , the  final speed in m/s of the 10.0 kg is 2.53 m/s .

8 0
3 years ago
Which angle is in standard position? On a coordinate plane, 2 rays form an angle and both rays are not on the y- or x-axis. On a
DerKrebs [107]

Answer:

(C)On a coordinate plane, 2 rays form an angle. One ray sits on the x-axis.

Step-by-step explanation:

In the coordinate plane, an angle is said to be in standard position when its value is stated with respect to the x-axis.

Therefore, for an angle to be in a standard position, one of its rays must be on the x-axis.

From the given options, only Option C has a ray that sits on the x-axis. Therefore, it is the only angle in standard position.

3 0
3 years ago
Read 2 more answers
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