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2 years ago

Estimate the quotient: 1628 ÷ 8 answer choices 168 162 160 260 106

Mathematics

1 answer:

slega [8]2 years ago

5 0

Answer:

203.5 so you can pick 168 because it's closer to the answer

Step-by-step explanation:

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3 years ago

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Solve Two Step Eqautions

VashaNatasha [74]

1. n=7
2. w= 7.75
3. f= -15
4. y = 66
5. g=42
6. p= 2

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3 years ago

THE LIN FAMILY HAS A FISH WITH DIFFERENT COLORS OF FISH . THERE ARE 7 BLUE FISH 4 GREEN FISH ,AND 4 YELLOW WHAT IS THE RATIO OF

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3 years ago

A manufacturing company with 450 employees begins a new product line and must increase their number of employees by 18%. How man

nika2105 [10]

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3 years ago

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let X = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

3 years ago