Answer:
(a) If r is any rational number and s is any irrational number, then r/s is rational
(b) The statement is false when r is 0
Step-by-step explanation:
Given
rational number
irrational number
irrational number
Solving (a): The negation
To get the negation of a statement, we only need to negate the end result
In other words, the number type of r and s will remain the same, but r/s will be negated.
So, the negation is:
rational number
irrational number
rational number
Solving (b): When r/s is irrational is false
Given that:
irrational number
Set r to 0
So:
![\frac{r}{s} = \frac{0}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Br%7D%7Bs%7D%20%3D%20%5Cfrac%7B0%7D%7Bs%7D)
-- rational
<em>Hence, the statement is false when r is 0</em>
divide by I and r so t=p/(ir)
Answer: option A, 3x + 5
first, i rewrote it and removed the parentheses.
2x - 4 + x + 9
then, i collected the like terms.
3x + 5
Answer is given below
Step-by-step explanation:
given data
average length of all 1015 fishes = 98.06 mm
randomly selects 50 fishes average length = 101.04 mm
solution
- When we get here, we mean to measure, so here we measure a fish in a square lake.
- And the variable means that a fish varies from fish to fish, so the length of the fish in the squares
- parameter mean that all individuals in the population so the parameter is average length of all 1015 fish in square lake
- statics is selct of individual in sample so statistic is average length of random sected so fish in square lake
Answer:
4.12
Step-by-step explanation:
≈ 4.12