Ask question

Ask question

All categories

3 years ago

11

(–3)^5 What does the ^ mean? Multiplication?

2 answers:

stira [4]3 years ago

6 0

Yes it’s means multiplication.

Vladimir79 [104]3 years ago

5 0

Answer:

-15

Step-by-step explanation:

You might be interested in

The expression (3z2) (2z4) is equivalent to which of the following numerical expression? A. 6z8 B. 6z6 C. 5z6 D. 5z8

balandron [24]

B.6z6
When you multiply with exponents you add the exponents together 4+2=6
Then just multiply the #s 2×3=6

7 0

3 years ago

Read 2 more answers

What is the mean absolute deviation of the data set? 12, 15, 7, 4, 9, 10, 9, 6

bearhunter [10]

Here is an example:
Find the MAD of 2,4,6,8 Step 1 : Find the mean of the data : (2+4+6+8) / 4 = 20/5 = 4 Step 2 : Find the distance between each data and mean. Distance between 2 and 5 is 3 Distance between 4 and 5 is 1 Distance between 6 and 5 is 1 Distance between 8 and 5 is 3
Step 3 : Add all the distances : 3+1+1+3 = 8
Step 4 : Divide it by the number of data : 8 / 4 = 2 2 is the average absolute deviation.

3 0

3 years ago

Triangle ABC is a right triangle.

BabaBlast [244]

U can use the second last one

X + 90 = 2x + 40

6 0

4 years ago

Read 2 more answers

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago

Please help with 16 and 17 those are hard

notka56 [123]

The answer to number 17 is c

6 0

3 years ago