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pantera1 [17]
3 years ago
6

Solve the inequality V/3+12>7

Mathematics
2 answers:
Ivanshal [37]3 years ago
7 0

Answer:

V > -15

Step-by-step explanation:

\frac{V}{3} +12>7\\\\\frac{V}{3}>-5\\\\V>-15

Nat2105 [25]3 years ago
4 0

Answer:

V > -15

Step-by-step explanation:

V/3 + 12 > 7

V/3 > -5

V > -15

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Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
A man earns $11.62 for each of the first 36 hours he works in one week and $17.43 in overtime pay for each additional hour he wo
11Alexandr11 [23.1K]

Answer:

21❄️....................

8 0
3 years ago
How do I go about solving this? <br> ((-3) -2) x 5
ss7ja [257]

Answer:

-25

Step-by-step explanation:

i got -25. i just used a calculator

8 0
3 years ago
WILL GIVE BRAINLEIST HELP ASAP (20 points!!)
Margarita [4]

hope it helps you pls mark me brainliest pls.

3 0
3 years ago
I need help please it’s ASAP
malfutka [58]

The interquartile range of the data is equal to 2.18.

<h3>What is an interquartile range?</h3>

The interquartile range is a measure of where a data set's "middle fifty" is located. Whereas a range is a measure of where the start and end of a set are, an interquartile range is a measure of where the majority of the values are.

Given data is { 1.56,1.77,2.22,2.35,2.45,2.77,3.26,4.35,5.23,6.02}.

The upper limit is, and the median is 2.22.

{ 1.56,1.77,<u>2.22</u>,2.35,2.45,2.77}

The lower limit is, and the median is 4.35.

{2.77,3.26,<u>4.35</u>,5.23,6.02}

The interquartile range will be calculated as,

IQR = 4.35 - 2.22

IQR = 2.18

To know more about interquartile range follow

brainly.com/question/21270410

#SPJ1

5 0
1 year ago
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