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sergiy2304 [10]
3 years ago
12

Importance of Computer in the world​

Computers and Technology
2 answers:
borishaifa [10]3 years ago
7 0

Computers help us learn and they help us express ourselves. Without them, our world would be very different.

Hope I helped!

~Mschmindy

~~~~~~~~~~~~~~~~~~~~~~~~

Serhud [2]3 years ago
7 0

Answer:

Explanation:

Computers are unavoidable fact in the world today. I.e to reduce human work n power we can use computers to process and get useful output. Computers keeps data larger than what human can keep in the book I love computers

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Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in t
o-na [289]

Answer:

I am writing a Python program. Let me know if you want the program in some other programming language.        

import string  #to use string related functions

def wordcount(filename):  # function that takes a text file name as parameter and returns the number of occurrences of every word in file

   file = open(filename, "r")  # open the file in read mode

   wc = dict()  # creates a dictionary

   for sentence in file:  # loop through each line of the file

       sentence = sentence.strip()  #returns the text, removing empty spaces

       sentence=sentence.lower() #converts each line to lowercase to avoid case sensitivity

       sentence = sentence.translate(sentence.maketrans("", "", string.punctuation))  #removes punctuation from every line of the text file

       words = sentence.split(" ")  # split the lines into a list of words

       for word in words:  #loops through each word of the file

           if len(word)>2:  #checks if the length of the word is greater than 2

               if word in wc:  # if the word is already in dictionary

                   wc[word] = wc[word] + 1  #if the word is already present in dict wc then add 1 to the count of that word

               else:  #if the word is not already present

                   wc[word] = 1  # word is added to the wc dict and assign 1 to the count of that word                

   for w in list(wc.keys()):  #prints the list of words and their number of occurrences

       print(w, wc[w])  #prints word: occurrences in key:value format of dict        

wordcount("file.txt") #calls wordcount method and passes name of the file to that method

Explanation:

The program has a function wordcount that takes the name of a text file (filename) as parameter.

open() method is used to open the file in read mode. "r" represents the mode and it means read mode. Then a dictionary is created and named as wc. The first for loop, iterates through each line (sentence) of the text file. strip() method is used to remove extra empty spaces or new line character from each sentence of the file, then each sentence is converted to lower case using lower() method to avoid case sensitivity. Now the words "hello" and "Hello" are treated as the same word.

sentence = sentence.translate(sentence.maketrans("", "", string.punctuation))  statement uses two methods i.e. maketrans() and translate(). maketrans() specifies the punctuation characters that are to be deleted from the sentences and returns a translation table. translate() method uses the table that maketrans() returns in order to replace a character to its mapped character and returns the lines of text file after performing these translations.

Next the split() method is used to break these sentences into a list of words. Second for loop iterates through each word of the text file. As its given to ignore words of length 2 or less, so an IF statement is used to check if the length of word is greater than 2. If this statement evaluates to true then next statement: if word in wc:   is executed which checks if the word is already present in dictionary. If this statement evaluates to true then 1 is added to the count of that word. If the word is not already present  then the word is added to the wc dictionary and 1 s assigned to the count of that word.

Next the words along with their occurrences is printed. The program and its output are attached as screenshot. Since the frankenstein.txt' is not provided so I am using my own text file.

4 0
2 years ago
Why is it now difficult for computer technology to maintain the pace of
KatRina [158]

It now difficult for computer technology as manufacturing cannot keep up with overwhelming transistor demand.

<h3>What was Moore's Law ?</h3>

Moore's Law is the one that talks about the fact that the number of transistors on a microchip is one that often goes up about two years always, even if the cost of computers is reduced.

Based on the above, It now difficult for computer technology as manufacturing cannot keep up with overwhelming transistor demand.

Learn more about computer technology  from

brainly.com/question/24912812

#SPJ1

6 0
2 years ago
Briefly explain the following terms and concepts:
morpeh [17]

Answer:

Answer below

Explanation:

Maximum transmission unit (MTU)

A maximum transmission unit (MTU) is the largest packet or frame size that is usually specified in Eight-bit bytes, which can be sent in a packet or frame-based network such as the internet.  

Longest Prefix Match

Longest prefix match is an algorithm used by routers in Internet Protocol to lookup the IP prefix that will likely be the terminal point of the next hop from the router.

CIDR and Subnet Mask

CIDR, known in full as Classless inter-domain routing, is a set of IP standards that is used to make customized identifiers for networks and individual devices.  

A subnet mask separates the internet protocol (IP) address into the network address and host address.

 

Switching Fabric

Switching fabric is simply an arrangement of the elements of a communication network also known as network topology, whereby the nodes of the network are seen to interconnect with one or more network switches.

7 0
2 years ago
Read 2 more answers
The ________ view in access looks similar to an excel spreadsheet.
ch4aika [34]
Datasheet 
<span>The datasheet view in access looks similar to an excel spreadsheet.</span>
6 0
2 years ago
Display all the natural numbers from 1 to 100 that are exactly divisible by 3 and 7 using FOR … NEXT. Without using Mod
Tcecarenko [31]

Answer:

FOR i% = 1 TO 100

 IF ((i%\3) = i%/3) AND ((i%\7) = i%/7)  THEN

   PRINT i%

 END IF

NEXT i%

Explanation:

Of course using MOD would be cleaner, but another way to check if a number is integer divisable is to compare the outcome of an integer division to the outcome of a floating-point division. If they are equal, the division is an integer division.

The program outputs:

21

42

63

84

6 0
3 years ago
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