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Evgesh-ka [11]
4 years ago
14

The famous study entitled ""Protection Analysis: Final Report"" focused on a project undertaken by ARPA to understand and detect

__________ in operating systems security.
Computers and Technology
1 answer:
LUCKY_DIMON [66]4 years ago
8 0

Answer:

vulnerabilities

Explanation:

According to my research on information technology, I can say that based on the information provided within the question this was designed to focus, understand, and detect vulnerabilities in operating system security. Vulnerabilities are technical weak spots within a operating systems code that can be exploited and hacked in order to gain access to the system.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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A software EULA is an agreement related to which of the following?
densk [106]

A software EULA is an agreement related to the terms of use of the software

the terms of use of the software

<u>Explanation:</u>

EULA stands for End User License Agreement. It can be defined as an agreement related to the terms of use of the software. EULA provides the user with all the details and any restrictions that have been imposed on the application by the developer.

In order to use the software, the user has to agree with all the terms and conditions specified in the EULA. The most common restriction imposed on an application/software is that it shouldn't be shared with anyone, in proprietary software.

7 0
3 years ago
Read 2 more answers
A(n) __________ is a common list operation used in programming. Its purpose is to iterate through a list of items, one item at a
34kurt
Linear search

You implement this algorithm by iterating over each item, and checking if the item matches what you are searching for.

It is linear because it takes a linear amount of time to search for an item.
5 0
3 years ago
In a linked chain implementation of a stack ADT the performance of popping am emtry from the stack is
Mice21 [21]

Answer:

B.O(1)

Explanation:

When we are implementing ADT stack using linked chain we can pop an entry from the stack having O(1) time complexity because in linked chain we have the head or top pointer in linked chain only.Popping and pushing in stack happens on only one end that is top.So we have move to move top in linked chain to the next and delete prev node.

8 0
3 years ago
Which of the following statements about Java Class Libraries is false? Question 18 options: A) An advantage of using Java class
Novosadov [1.4K]

Answer:

D) Java class libraries are not portable

Explanation:

The Java Class Library (JCL) is an array of enthusiastically loadable libraries that Java applications can identify and refer to at run time. Since the Java Platform is independent of any particular operating system, applications can’t depend on any of the platform-native libraries.

The library is a massive collection and works of prebuilt classes that is distributed through the Java SE platform.

6 0
3 years ago
In Coral programming: A half-life is the amount of time it takes for a substance or entity to fall to half its original value. C
viva [34]

Answer:

Yes, it will be after 6 hours: 50 mg, after 12 hours: 25 mg, and after 18 hours: 12.5 mg

Explanation:

Remember coral is a functional programming language and follows Pythons functional programming paradigm. Remember Python supports functional, imperative as well as OOPS paradigm.

The function will be:

def void calcamtleft(int amt):

   integer a=6

   integer time=6

   integer i=1

   while amt> 0:

       amt=amt/2

       print("After"+time+"  hours:" +amt+"mg")

       i++

       time=a* i

Hence in first loop amt=100

new amt=100/2=50

After 6 hours: 50 mg ( this will be printed)

i will increment then, and time will be = 6 *2 =12

now input amt=50

new amt=50/2=25

After 12 hours 25 mg (this will be output)

i will increment then, and time will be = 6 *3 =18

now input amt=25

new amt=25/2=12.5

After 18 hours 12.5 mg (this will be output)

i will increment then, and time will be = 6 *4 =24

now input amt=12.5/2= 6.25

new amt=6.25/2= 3.125

After 24 hours 3.125 mg (this will be output)

i will increment then, and time will be = 6 *5 =30

now input amt=3.125

new amt=3.125/2= 1.5625

After 30 hours 1.5625 mg

And this will continue till amt>0

7 0
3 years ago
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