Those are alternate interior angles and are equal. B.5x=80 x=16.
\left[x _{2}\right] = \left[ 6+\sqrt{33}\right][x2]=[6+√33]
![\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5Be%5E%7B2y%7D-y%5Ccos%20xy%5Cright%5D%3D2e%5E%7B2y%7D-%5Ccos%20xy%2Bxy%5Csin%20xy)
![\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20x%7D%5Cleft%5B2xe%5E%7B2y%7D-y%5Ccos%20xy%2B2y%5Cright%5D%3D2e%5E%7B2y%7D%2By%5Csin%20xy)
The partial derivatives are not equal, so the equation is not exact.
1. Plug in the 3 in all the x’s that are in the equation:
(3)2 + y2 = for x2 + y2
(3)2 - y2 = for x2 - y2
This would get you for both equations..
6 + y2 = for x2 + y2
6 - y2 = for x2 - y2
2. Now let’s plug in the value of y which is -4:
6 + (-4)2 = for x2 + y2
6 - (-4)2 = for x2 + y2
This would get you for both equations...
-2 = x2 + y2
14 = x2 - y2
Hope this helped, have an awesome day!