All categories

2 years ago

Brainliest + 20 points to whoever helps!!!

Mathematics

1 answer:

Darya [45]2 years ago

8 0

Answer:

D. The standard deviation is known and n > 30.

Step-by-step explanation:

Your sample size is greater than 30.
Data points should be away from each other.
Your data should be commonly categorized.
Your data should be randomly picked from a population. Each item should have an equal chance of being selected.
The sample sizes should be equal.

You might be interested in

After arianna completed some work, she figured she still had 78 21/100 pictures to paint. if she completed another 34 23/25 pict

dezoksy [38]

Subtract the number she completed from what she had left to paint originally.

The fractions have different denominators so first step is to rewrite the fractions with a common denominator.

23/25 can be rewritten as 92/100

Now you have 78 21/100 - 34 92/100

Because 21/100 is smaller than 92/100 subtract 1 whole number from 78 and rewrite 1 as 100/100 and add that to the fraction.

78 21/100 becomes 77 121/100

Now subtract :

77 121/100 - 34 92/100

77-34 = 43

And 121/100 - 92/100 = 29/100

Combine to get 43 and 29/100

3 0

2 years ago

Solve any evens for 20 points apiece

Vlad1618 [11]

? what do you mean. do you have questions that need to be solved?

5 0

2 years ago

Let A= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose an element of A is randomly selected. What is the probability that it belongs to

gregori [183]

<h3>Answer: 3/5</h3>

============================================================

Explanation:

The set {1, 2}U{2, 6, 7, 9}U{5, 6, 7} simplifies to {1,2,5,6,7,9} after we combine everything and sort the values. We toss any duplicates.

Let B = {1,2,5,6,7,9}

There are 6 items in set B out of 10 items in set A.

The probability of landing in set B, if you pick something randomly from A, is 6/10 = 3/5

8 0

2 years ago

Read 2 more answers

A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic

Ket [755]

Answer:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

Step-by-step explanation:

Data given and notation

$\bar X=5.25$ represent the sample mean

$s=3.98$ represent the sample standard deviation

$n=54$ sample size

$\mu_o =4.73$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:

Null hypothesis: $\mu =4.73$

Alternative hypothesis: $\mu \neq 4.73$

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

7 0

2 years ago

A box contains 6 red marbles, 4 green marbles, 3 blue marbles, and 2 yellow marbles. If one marble is chosen at random, what is

blondinia [14]

Answer:

0.2

Step-by-step explanation:

6+4+3+2=total no of marble

=15

no of blue marble 3

$\frac{3}{15} \\ = \frac{1}{5 } \\ = 0.2$

3 0

2 years ago