Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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<span>Given that your favorite soccer team has 3 games left to finish the season and that the
outcome of each game can be win, lose, or tie.
The number of possible
outcomes that exist is given by
</span>
Answer:
1/2x
Step-by-step explanation:
To solve this type of fraction you need to times the inverse of the bottom fractal, both over and under. In this case the inverse of 1/2 is 2/1
Answer:
x=137
y=525-137
y=388
Step-by-step explanation:
Let the student tickets be x
Let the geral Admission tickets be y
x+y=525
y=525-x
4x+6y=2876 (subsitute for y)
4x+6(525-x)=2876
4x+3150-6x=2876
-2x=-274
x=137
y=525-137
y=388
Hence, about 137 childern tickets were sold and 388 gernal admission tickets were sold.
Paul.
Answer:
$700.00 porque si cada uno recaudo por lo menos $25.00 entonces multiplicas 28 por los estudiantes y $25.00 por la cantidad menos recaudada equivalente a $700.00
Step-by-step explanation:
