2 years ago

Consider the region bounded by

1 answer:

Montano1993 [528]2 years ago

4 0

The equation is a circle centered at the origin with radius 8 (sqrt(64))
Therefore, the bounded region is just a quarter circle in the first quadrant.

Riemann Sum: ∑⁸ₓ₋₋₀(y²)Δx=∑⁸ₓ₋₋₀(64-x²)Δx

Definite Integral: ∫₀⁸(y²)dx=∫₀⁸(64-x²)dx

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I need help with 2 and 5 and I need you to right down how you did it plz and thank you

anastassius [24]

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2 years ago

Solve the following systems of inequalities and select the correct graph: 2x-y>4 x+y< -1

Serga [27]

Answer:

Step-by-step explanation:

2x - y > 4 ⇒ y < 2x - 4

x + y < - 1 ⇒ y < - x - 1