1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio039 [100]
3 years ago
12

Which of the following situations can be modeled by the expression -4 + (-7)?

Mathematics
2 answers:
dybincka [34]3 years ago
6 0
The answer to the question is the second story problem
Dafna1 [17]3 years ago
6 0

Answer:

The answer to the question is the second story problem

Step-by-step explanation:

You might be interested in
The chorus teacher plans to arrange the students in equal rows. Only the girls or boys will be in each row. What is the greatest
emmainna [20.7K]

Answer:

2

Step-by-step explanation:

68+48=116

116÷16=7.24 (wrong)

116÷12=9.7 (wrong)

116÷4=29 (lowest even)

116÷2=58 (highest even)

If I'm wrong, let me know

8 0
2 years ago
Which two prime numbers' product is 226
saw5 [17]

Answer:

<h2>Solution: Since, the prime factors of 226 are 2, 113. Therefore, the product of prime factors = 2 × 113 = 226.</h2>

Step-by-step explanation:

<h2>(。♡‿♡。)______________________</h2><h2><em><u>PLEASE</u></em><em><u> MARK</u></em><em><u> ME</u></em><em><u> BRAINLIEST</u></em><em><u> AND</u></em><em><u> FOLLOW</u></em><em><u> M</u></em><em><u> </u></em><em><u> </u></em><em><u>E </u></em><em><u>AND</u></em><em><u> SOUL</u></em><em><u> DARLING</u></em><em><u> TEJASWINI</u></em><em><u> SINHA</u></em><em><u> HERE</u></em><em><u> ❤️</u></em></h2>
4 0
3 years ago
Read 2 more answers
Help please. If answer is good i'll mark brainliest ;)
Mariulka [41]

You can't cheat you can't ask someone for help and ask for answers ;-;

6 0
3 years ago
What is the square root of 325
AlexFokin [52]
\sqrt{325}=\sqrt{25\cdot13}=\sqrt{25}\cdot\sqrt{13}=5\sqrt{13}\approx18.03
6 0
3 years ago
Read 2 more answers
For a standard normal random variable, what z-score has (a) probability 0.175 to the right?
Mumz [18]
Answer: 0.935

Explanation: 

Let S = z-score that has a probability of 0.175 to the right. 

In terms of normal distribution, the expression "probability to the right" means the probability of having a z-score of more than a particular z-score, which is Z in our definition of variable Z. In terms of equation:

P(z ≥ S) = 0.175   (1)

Equation (1) is solvable using a normal distribution calculator (like the online calculator in this link: http://stattrek.com/online-calculator/normal.aspx). However, the calculator of this type most likely provides the value of P(z ≤ Z), the probability to the left of S.

Nevertheless, we can use the following equation:

P(z ≤ S) + P(z ≥ S) = 1 
⇔ P(z ≤ S) = 1 - P(z ≥ S)  (2)

Now using equations (1) and (2):

P(z ≤ S) = 1 - P(z ≥ S)
P(z ≤ S) = 1 - 0.175 
P(z ≤ S) = 0.825

Using a normal distribution calculator (like in this link: http://stattrek.com/online-calculator/normal.aspx),

P(z ≤ S) = 0.825
⇔ S = 0.935 

Hence, the z-score of 0.935 has a probability 0.175 to the right.
7 0
3 years ago
Other questions:
  • A spinner has three sections. The table shows the results of spinning the arrow on the spinner 80 times. What is the experimenta
    5·1 answer
  • Simon does some shopping on the Internet he buys 4cds at 7.39 each
    8·2 answers
  • in a poll 303 students voted . nominee d received 2/3 of the votes how many votes did nominee d receive​
    10·1 answer
  • What's the half of 93
    8·2 answers
  • 4 1/2 cups of flour make 2 batches of cookies. How much flour per batch
    13·2 answers
  • Does the following table show a proportional relationship between the variables ggg and hhh?
    13·1 answer
  • 1) How is unit rate related to slope or rise over run?
    12·1 answer
  • If the value of 6 coins is $0.56, what are the coins?​
    6·1 answer
  • Solve the expression 7x + 8, x=4
    15·2 answers
  • Please help besties
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!