Initially, Greg has a total of 60 DVDs and CDs in his collection. He then sold 1/8 of his CDs and 1/2 of his DVDs. If the number
of DVDs he sold is twice the number of CDs he sold, how many DVDs did he sell?
1 answer:
Answer:
10 DVD's were sold.
Step-by-step explanation:
c = number of CD's
d = number of DVD's
so we know:
c + d = 60
2*c/8 = d/2
this can be solved:
d = 60 - c
2c / 8 = (60-c)/2
4*(2c/8) = 4*(60-c)/2 [multiply by 4]
c = 120 - 2c
3c = 120
c = 40
d = 60-40 = 20
So Greg had 40 CD's and 20 DVD's. He sold half of his DVD's, i.e., 20/2=10 and 1/8 of his CD, i.e., 40/8 = 5
You might be interested in
Answer:

Step-by-step explanation:



Answer:
Bill has $21.
Step-by-step explanation:
There's $135. 84/4=21. At the same time, 21+9=30. 30+21+84=135.
Answer:
A. .25
B. .95
C. .75
D. .42
Step-by-step explanation:
Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
What am I supposed to be helping with the picture you took is only showing examples