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Dafna11 [192]
3 years ago
5

Initially, Greg has a total of 60 DVDs and CDs in his collection. He then sold 1/8 of his CDs and 1/2 of his DVDs. If the number

of DVDs he sold is twice the number of CDs he sold, how many DVDs did he sell?
Mathematics
1 answer:
poizon [28]3 years ago
5 0

Answer:

10 DVD's were sold.

Step-by-step explanation:

c = number of CD's

d = number of DVD's

so we know:

c + d = 60

2*c/8 = d/2

this can be solved:

d = 60 - c

2c / 8 = (60-c)/2

4*(2c/8) = 4*(60-c)/2    [multiply by 4]

c = 120 - 2c

3c = 120

c = 40

d = 60-40 = 20

So Greg had 40 CD's and 20 DVD's. He sold half of his DVD's, i.e., 20/2=10 and 1/8 of his CD, i.e., 40/8 = 5

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