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3 years ago

6

in which group does each element have a total of four electrons in the outermost principal energy level

1 answer:

marta [7]3 years ago

7 0

Answer:

Group 14

Explanation:

The elements of the Periodic Table are arranged into 18 Groups.

Among the "main group elements" — those in Groups 1, 2 and 13 to 18 — the number of valence electrons — the number of electrons in the outermost energy level — corresponds to the last digit of the Group number.

Thus, Group 14 contains the elements with four valence electrons — C, Si, Ge, Sn, Pb, and Fl.

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The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co

garri49 [273]

Answer:

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater ( $m_{sw}$ ), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

$m_{sw} = \rho_{sw}\cdot V_{sw}$

Where:

$\rho_{sw}$ - Density of seawater, measured in grams per liters.

$V_{sw}$ - Volume of seawater, measured in liters.

If $V_{sw} = 1.5\times 10^{21}\,L$ and $\rho_{sw} = 1030\,\frac{g}{L}$ , then:

$m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)$

$m_{sw} = 1.545\times 10^{24}\,g$

The total mass of sodium chloride is determined by the following ratio:

$r = \frac{m_{NaCl}}{m_{sw}}$

$m_{NaCl} = r\cdot m_{sw}$

Given that $m_{sw} = 1.545\times 10^{24}\,g$ and $r = 0.035$ , the total mass of sodium chloride in all the seawater in the world is:

$m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)$

$m_{NaCl} = 5.408\times 10^{22}\,g$

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

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4 years ago

During _______ materials move into the cell while during ______ materials move out of the cell.

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D. Endocytosis ; Exocytosis

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4 years ago

In your own words, explain the periodic law.

mote1985 [20]

States that the properties of elements are periodic or recurring and are correlated to their atomic number.

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4 years ago

Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30x10⁻⁸ at 700°C:2H₂S(g) ⇄ 2H₂(g) + S₂(g) If 0

astra-53 [7]

the equilibrium concentration of H₂(g) at 700°C = 0.00193 mol/L

0.00193 mol/L

Given that:

numbers of moles of H₂S = 0.59 moles

Volume = 3.0-L

Equilibrium constant = 9.30 × 10⁻⁸

The equation for the reaction is given as :

2H₂S ⇄ 2H₂(g) + S₂(g)

The initial concentration of H₂S =

The initial concentration of H₂S =

= 0.1966 mol/L

The ICE table is shown be as :

2H₂S ⇄ 2H₂(g) + S₂(g)

Initial 0.9166 0 0

Change -2 x +2 x + x

Equilibrium (0.9166 - 2x) 2x x

(since 2x < 0.1966 if solved through quadratic equation)

The equilibrium concentration for H₂(g) = 2x

∴

= 0.00193 mol/L

Thus, the equilibrium concentration of H₂(g) at 700°C = 0.00193 mol/L

To know more about equilibrium concentration

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A line has a slope of 5 and a y-intercept of -2.

KiRa [710]

Answer:

+T919919 mean the x- intercept of the line

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