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3 years ago

How would an electron shell model of an oxygen atom (O) appear after the atom has formed chemical bonds?

Chemistry

2 answers:

inessss [21]3 years ago

8 0

oxygen atomic number is 8.

electron configuration of O is 2,6

therefore O has 6 valence electrons. valence electrons are electrons in the outermost shell that are involved in chemical bonds

atoms to become stable should fulfill the octet rule. This is where the outermost shell should have 8 electrons

so atoms with incompletely filled outer shells take part in chemical bonds to gain a complete octet and to become stable

So O too after forming a chemical bond would have 8 electrons in the outermost shell.

correct answer is

c. It would have eight electrons in the outermost shell.

MrMuchimi3 years ago

6 0

Answer:

it C I just took the test hope this helps!!!

Explanation:

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Can someone answer this chemistry question

Natalka [10]

Explanation:

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3 years ago

How many quarters have the same value as 85 dimes? Use the equality 4 quarters = 10 dimes.?

marissa [1.9K]

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3 years ago

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A scientist is comparing 2 samples of the same compound. One is pure and the other is impure. The compound is a solid at room te

wariber [46]

Answer:

A glass of mineral water is not pure water.

Explanation:

Pure chemical substances

Pouring water into a glass from a bottle

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3 years ago

Drag the tiles to the correct boxes. Not all tiles will be used. The oxidation number of oxygen is -2, and that of chlorine is -

Evgen [1.6K]

Answer:

That oxidation number of chlorine is -1 while that of oxygen is -2

Explanation:

When it comes to manganese chloride to stabilize the chlorine Ion. Two manganese ions shall be required. Hence the formula for the compound becomes $M_nCl_2$ while the formula for manganese (iv) chloride will be $M_nCl_4$ similarly.

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3 years ago

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hammer [34]

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Explanation:

The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.

Alkaline earth metals donate 2 valence electrons to acquire noble gas configuration.

For example: Berrylium is the first alkaline earth metal with atomic number of 4 and thus has 4 electrons

Electronic configuration of berrylium:

$[Be]:4:1s^22s^2$

Berrylium atom will loose two electrons to gain noble gas configuration and form berrylium cation with +2 charge.

$[Be^{2+}]:2:1s^2$

Thus Elements donate 2 electron to produce a cation with a 2+ charge are alkaline earth metals.

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3 years ago