Which physical property refers to the temperature at which a substance in a solid state transforms to a liquid state?
1 answer:
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Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is,
Explanation :
The given balanced reaction is,
Given:
Moles of hexane = 0.121 mol
= -8326 kJ/mol
The negative sign indicate that the reaction exothermic or amount of heat released.
As, 1 mole of hexane released heat = 8326 kJ
So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈
Therefore, the heat released by the combustion of 1.121 mol of hexane is .