HDSJDHAJ SOMEONE HELP ME IM ABOUT TO FAIL MY SCIENCE CLASS
2 answers:
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Explanation:
The given data is as follows.
q = 69.0 kJ = 69000 J (as 1 kJ = 1000 J),
mass (m) = 8.10 kg = 8100 g (as 1 kg = 1000 g)
= (33.9 + 273) K = 306.9 K
C = 4.18 J/gK
As we know that the relation between heat and change in temperature is as follows.
q =
Putting the values into the above formula to calculate the final temperature as follows.
q =
69000 J =
69000 J =
= 2.037 K
= (2.037 + 306.9) K
= 308.9 K
or, = 309 K (approx)
Thus, we can conclude that the new temperature of the water bath is 309 K.