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dlinn [17]
3 years ago
7

Compute: (4 + 9) − 3(6) ÷ 2 + 8

Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0
The answer is 12

Step 1. Perform the operations inside the parenthesis:
(4 + 9) − 3(6) ÷ 2 + 8 = 13 - 18 ÷ 2 + 8

Step 2. Division has advantage over subtraction and addition:
13 - 18 ÷ 2 + 8 = 13 - 9 + 8

Step 3. Subtract and add:
13 - 9 + 8 = 12
kirza4 [7]3 years ago
4 0
Use pedmas, the correct answer is 12
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Therefore, the sampling distribution of \bar{x} is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The 95% interval estimate of the population mean \mu is

LCL = 7.431 hours to UCL = 10.569 hours

Step-by-step explanation:

Let X be the number of hours a legal professional works on a typical workday. Imagine that X is normally distributed with a known standard deviation of 12.6.

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\sigma = 12.6 \: hours

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

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n = 250

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\bar{x} = 9 \: hours  

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 \mu = \bar{x} = 9 \: hours

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$ s = {\frac{12.6}{\sqrt{250} }  $

s = 0.7969 \: hours

Therefore, the sampling distribution of \bar{x} is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The population mean confidence interval is given by

\text {confidence interval} = \mu \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sampling size, s is the sample standard deviation and  is the t-score corresponding to a 95% confidence level.

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 250 - 1 = 249

From the t-table at α = 0.025 and DoF = 249

t-score = 1.9695

MoE = t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\\\MoE = 1.9695\cdot \frac{12.6}{\sqrt{250} } \\\\MoE = 1.9695\cdot 0.7969\\\\MoE = 1.569\\\\

So the required 95% confidence interval is

\text {confidence interval} = \mu \pm MoE\\\\\text {confidence interval} = 9 \pm 1.569\\\\\text {LCI } = 9 - 1.569 = 7.431\\\\\text {UCI } = 9 + 1.569 = 10.569

The 95% interval estimate of the population mean \mu is

LCL = 7.431 hours to UCL = 10.569 hours

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<span>Carla is renting a canoe. It’s cost $80 for 2 hours and $160 for 4 hours. What is the rate per hour?

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