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3 years ago

How do you solve 4x 5y = -7 and 3x - 6y = 24 using matrices?

1 answer:

6 0

Aw yis

take the coefients and put them in rows

$\left[\begin{array}{ccc}4&5&|-7\\3&-6&|24\end{array}\right]$
divide 2nd row by 3
$\left[\begin{array}{ccc}4&5&|-7\\1&-2&|8\end{array}\right]$
multiply 2nd row by -4 and add to top one
$\left[\begin{array}{ccc}0&13&|-39\\1&-2&|8\end{array}\right]$
divide top row by 13
$\left[\begin{array}{ccc}0&1&|-3\\1&-2&|8\end{array}\right]$
multiply top row by 2 and add to bottom row
$\left[\begin{array}{ccc}0&1&|-3\\1&0&|2\end{array}\right]$

x=2
y=-3

You might be interested in

Examples of data presentation in math

myrzilka [38]

Answer:

Data Presentation - Tables

Tables are a useful way to organize information using rows and columns. Tables are a versatile organization tool and can be used to communicate information on their own, or they can be used to accompany another data representation type (like a graph). Tables support a variety of parameters and can be used to keep track of frequencies, variable associations, and more.

For example, given below are the weights of 20 students in grade 10:

50, 45, 48, 39, 40, 48, 54, 50, 48, 48, \\ 50, 39, 41, 46, 44, 43, 54, 57, 60, 45.

50,45,48,39,40,48,54,50,48,48,

50,39,41,46,44,43,54,57,60,45.

To find the frequency of 4848 in this data, count the number of times that 4848 appears in the list. There are 44 students that have this weight.

The list above has information about the weight of 2020 students, and since the data has been arranged haphazardly, it is difficult to classify the students properly.

To make the information more clear, tabulate the given data.

\begin{array}{c}\\ \text{Weights in kg} & & & \text{Frequency} \\ 39 & & & 2 \\ 40 & & & 1 \\ 41 & & & 1 \\ 43 & & & 1 \\ 44 & & & 1 \\ 45 & & & 2 \\ 46 & & & 1 \\ 48 & & & 4 \\ 50 & & & 3 \\ 54 & & & 2 \\ 57 & & & 1 \\ 60 & & & 1 \end{array}

Weights in kg

Frequency

This table makes the data more easy to understand.

5 0

3 years ago

g A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a rando

Tema [17]

Answer:

We accept the null hypothesis, that is, the the mean amount of garbage per bin is not different from 50.

Step-by-step explanation:

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50.

This means that the null hypothesis is:

$H_{0}: \mu = 50$

And the alternate hypothesis is:

$H_{a}: \mu \neq 50$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

50 tested at the null hypothesis:

This means that $\mu = 50$

In a random sample of 36 bins, the sample mean amount was 50.67 pounds and the sample standard deviation was 3.9 pounds.

This means that $n = 36, X = 50.67, \sigma = 3.9$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{50.67 - 50}{\frac{3.9}{\sqrt{36}}}$

$z = 1.03$

p-value:

Since we are testing if the mean is differente from a value and the z-score is positive, the pvalue is 2 multipled by 1 subtracted by the pvalue of z = 1.03.

z = 1.03 has a pvalue of 0.8485

1 - 0.8485 = 0.1515

2*0.1515 = 0.3030

0.3030 > 0.01, which means that we accept the null hypothesis, that is, the the mean amount of garbage per bin is not different from 50.

5 0

3 years ago

Determine the relationship between the two triangles and whether or not they can be

xz_007 [3.2K]

The photo wont load uhhhhh

5 0

3 years ago

Read 2 more answers

Ill mark btainlist pllssss helpp

Hatshy [7]

Answer:

1cm-----80000m

1cm-----8000000cm

1cm×3.275-----80km×3.275

3.275cm

3 0

3 years ago

Help!!! Need Anwser!!!

jolli1 [7]

Hello.

The answer is choice A. angle 1 = 118, angle 2 = 118

Explanation:

The four angles above are congruent (meaning the same) to the ones beneath.

Angles 1 and 2 are also congruent, so they will measure the same.

Lets label the angles above A, B, C, D. B being the known angle, which is 118°. The angles beneath can be labelled E, F, G, H.

∠B ≅ ∠D

∠ABCD ≅ ∠EFGH

∠BD ≅ ∠FH

FH (or 1 and 2) equal 118.

4 0

3 years ago