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erica [24]
3 years ago
11

In Need OF HELP !!!!!!!! ​

Mathematics
1 answer:
mestny [16]3 years ago
5 0
The answer you’re looking for is B
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The relationship between the length of one side of the Square, eggs, and the perimeter of the Square, why, can be represented in
oee [108]

Answer:

The points with coordinates (x, y) that are on the line of the equation of the line relationship between the side of a square, x and the perimeter, y include;

(1, 4), (2, 8), (3, 12) ....(n, 4·n).

Where n is a positive number.

Step-by-step explanation:

The formula to determine the length of the perimeter of a square is,

Length of the perimeter of a square = Length of a side of the square multiplied by 4.

That is Perimeter of square = Side of square × 4

The relationship between the length of one side of a square and the perimeter of the square can be represented by the equation

y = 4×d which is a straight line with a slope of 4 passing through the origin

Points o the line include

(1, 4), (2, 8), (3, 12), etc.

The x and y coordinates take the form

(x, 4·x)

5 0
3 years ago
A ladder that is 13 meters long is leaning against a wall. The distance between the foot of the ladder and the wall is 7 meters
Maksim231197 [3]
<h2>Answer:</h2>

The equation that is used to model the length of ladder in terms of x is:

                   x^2-7x-60=0

<h2>Step-by-step explanation:</h2>

We can model this problem with the help of a right angled triangle whose hypotenuse is 13 meters and the other two legs are x meters and (x-7) meters.

where x is the distance between the top of the ladder and the ground.

and (x-7) is the distance between the foot of the ladder and the wall.

Hence, using Pythagorean Theorem we have:

13^2=x^2+(x-7)^2\\\\i.e.\\\\169=x^2+x^2+49-14x\\\\i.e.\\\\169=2x^2-14x+49\\\\i.e.\\\\2x^2-14x+49-169=0\\\\i.e.\\\\2x^2-14x-120=0\\\\i.e.\\\\x^2-7x-60=0

                 Hence, the answer is:

                  x^2-7x-60=0

7 0
3 years ago
Read 2 more answers
Find an equation for the plane y=4x in cylindrical coordinates. (Type theta for θ in your answer.)
Paha777 [63]

Answer:

<h2><em>sinθ - 4cosθ = 0</em></h2>

Step-by-step explanation:

Given the equation of a plane in rectangular coordinates to be y = 4x.

The cylindrical coordinates of the axis is as given below;

x = rcosθ

y = rsinθ

z = z

Since there is no z coordinate in the equation of the plane given, we will only substitute x = rcosθ and y = rsinθ into the equation y = 4x and simply the result as shown;

y = 4x

rsinθ = 4( rcosθ)

rsinθ = 4rcosθ

sinθ = 4cosθ

sinθ - 4cosθ = 0

<em>Hence the equation for the plane in cylindrical coordinate is expressed as sinθ - 4cosθ = 0</em>

8 0
3 years ago
If the measure of xyz is 73 what is the measure of xy <br> a.146<br> b.73<br> c.36.5<br> d.107
icang [17]
146. They are asking for the angle XY, the blue line.

For instance, imagine it is 90 deg, instead of 73, it would cut the circle in two, and XY would be 180 deg. Imagine it would be 45 degrees, it would leave a quadrant, and that's 90 deg.

So the angle * 2 (they are different angles)

I think 'TheBestBrain' thought they were asking for the supplementary angle, but I think it is the arc length angle (blue line)

5 0
4 years ago
Read 2 more answers
Find the equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation 3/2x-2y=-
kondaur [170]

The equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2} is:

y = \frac{3}{4}x - \frac{15}{4}

<h3><u>Solution:</u></h3>

Given that line that passes through the point (1, -3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2}

We have to find equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c

Where "m" is the slope of line and "c" is the y-intercept

Let us first find slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2}

\frac{3}{2}x - 2y = \frac{-17}{2}

Rearrange the above equation into slope intercept form

\frac{3x}{2} + \frac{17}{2} = 2y\\\\y = \frac{3x}{4} + \frac{17}{4}

On comparing the above equation with slope intercept form y = mx + c,

m = \frac{3}{4}

So the slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2} is m = \frac{3}{4}

We know that slopes of parallel lines are equal

So the slope of line parallel to line having above equation is also m = \frac{3}{4}

<em><u>Now let us find the equation of line having slope m = 3/4 and passes through point (1 , -3)</u></em>

Substitute m = \frac{3}{4} and (x, y) = (1 , -3) in slope intercept form

y = mx + c

-3 = \frac{3}{4}(1) + c\\\\c = -3 - \frac{3}{4}\\\\c = \frac{-15}{4}

<em><u>Thus the required equation of line is:</u></em>

substitute m = \frac{3}{4} and c = \frac{-15}{4} in slope intercept form

y = \frac{3}{4}x + \frac{-15}{4}\\\\y =\frac{3}{4}x - \frac{15}{4}

Thus the equation of line is found out

3 0
3 years ago
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