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Alexxandr [17]
4 years ago
14

Which is the correct product of the significant figures 3.278 and 4.23? . A.14 . B.13.9 . C.13.86 . D.13.865 . E.13.86594 . . Ex

plain if you can please.
Mathematics
2 answers:
eimsori [14]4 years ago
6 0
To answer the question above, first, just multiply directly the numbers. 
                                 3.278 x 4.23 = 13.86594

The rule for the significant figures for multiplication of two or more numbers is that the number of significant figures of the product should be equal to the least number of significant figures of the factors. From the given above, the first factor has 4 significant figures and the second only has 3. Therefore, the product should only have 3 significant figures. The answer is letter B. 13.9
Ksenya-84 [330]4 years ago
5 0
Let us first multiply the numbers that are given in the question.
3.278 x 4.23 = 13.86594.
Now comes the important part of finding the correct answer. The first number has four significant figures and the second number has three significant figures. The result or the product of these two numbers should have three significant figures. The answer will then be 13.9. The correct option among all the options that are given in the question is option "B".
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Tanzania [10]

Answer:

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Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

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           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

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8 0
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Read 2 more answers
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