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mars1129 [50]
3 years ago
15

If the 2nd and 5th terms of a

Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

45

Step-by-step explanation:

The n th term of a GP is

a_{n} = ar^{n-1}

where a is the first term and r the common ratio

Given a₂ = 6 and a₅ = 48, then

ar = 6 → (1)

ar^{4} = 48 → (2)

Divide (2) by (1)

\frac{ar^4}{ar} = \frac{48}{6} , that is

r³ = 8 ( take the cube root of both sides )

r = \sqrt[3]{8} = 2

Substitute r = 2 into (1)

2a = 6 ( divide both sides by 2 )

a = 3

Thus

3, 6, 12, 24 ← are the first 4 terms

3 + 6 + 12 + 24 = 45 ← sum of first 4 terms

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Vaselesa [24]
4 x 10^6 is the answer to the questioin
7 0
3 years ago
Find the volume of the tetrahedron in the first octant bounded by the coordinate planes and the plane passing through (2 comma 0
SVETLANKA909090 [29]

Answer:

The volume of the tetrahedron is:

\frac{50}{3}=16.667

Step-by-step explanation:

The volume of the tetrahedron is given by the intersection of the planes x = 0, y = 0, z = 0 and the plane formed by the three points given.

The equation of the plane formed by the three points is:

Points: (2,0,0);(0,5,0);(0,0,4)

\pi :\frac{x}{2} +\frac{y}{5} +\frac{z}{4} =1

It can also be expressed as:

10x + 4y+5z=20

We have to calculate the triple integral, therefore we must define the domain:

The values of x are given by:

0≤x≤2

We will integrate the values of y between the y = 0 axis and the line formed when z = 0:

z=0 ⇒ 10x + 4y=2 ⇒ y=\frac{20-10x}{4} =

0\leq y \leq 5-\frac{5}{2}x

We will integrate the values of z between the plane z = 0 and the plane 10x + 4y+5z=20

10x + 4y+5z=20 ⇒ z=\frac{20-10x-4y}{5} =4-2x-\frac{4}{5}y

0\leq z \leq  4-2x-\frac{4}{5}y

The volume of the tetrahedron is:

\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \ \ \ \int\limits^{4-2x-\frac{4}{5}y }_{0} {z} \, dz\, dy \,dx

\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \frac{z^2}{2}|^{4-2x-\frac{4}{5}y}_0\, dy \,dx

\frac{z^2}{2}|^{z=4-2x-\frac{4}{5}y}_{z=0}=\frac{5}{25}(5x+2(y-5))^2

\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} {\frac{5}{25}(5x+2(y-5))^2}\, dy \,dx

\int\limits^{2}_{0} {-\frac{25}{6}(x-2)^3} dx=-\frac{25}{24} (x-2)^4|^{2}_{0}=\frac{50}{3}

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4 years ago
What is 1 4/5 times 2 1/3
frosja888 [35]

Answer:

4.2

Step-by-step explanation:

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3 years ago
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What is the answer of this question I need to know now
Rashid [163]
The answer is B, 240 is divisible by 3,4,5 and 8.
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Suppose a ten firm industry has total sales of $35 million per year. The largest firm have sales of $10 million, the third large
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Answer:

7 million

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