Thirty three because I'm just smart like that so you should believe me entirely.
Let x = number of adult tickets, and y = number of children tickets. One equation must deal with the number of tickets, and the other equation must deal with the revenue from the tickets.
Then x + y = 300 is the number of tickets
12x + 8y = 3280 is the revenue from the tickets.
Using the substitution method:
x + y = 300 ⇒ y = 300 - x ⇒ Equation (3)
12x + 8y = 3280 ⇒ 12x + 8(300-x) = 3280 ⇒ x = 220
y = 300 - x ⇒ y = 300-220 ⇒ 80
Therefore 220 adult tickets and 80 children's tickets were sold.
First rewrite it like this
1. y=5/4x
Then, make X the subject
2.4x=5/y
x=(5/y)÷4
3. Once done, simply replace x with h(x)^-1 and y with x
h(x)^-1= (5/x)÷4
Sorry I'm not very good at rearranging formula but hope this helps :)
Answer:900
Step-by-step explanation:
900/9=100
100x9=900
