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3 years ago

How u write an inequality for brigitte is shorter than 5 feet (brigitte height =h)

Mathematics

1 answer:

MArishka [77]3 years ago

4 0

Since Brigitte in shorter or lesser than 5 feet, h ges on the right of the lesser than symbol.
5 < h

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There is a red, orange, yellow, green, blue, and purple card placed in a box. (six total, one of each color). You are asked to r

GrogVix [38]

Answer:

Step-by-step explanation:

If you are doing probability with replacement they will all be 1/6 each time.

total there is 6/6. If you draw a yellow card first it's 1/6 then replace it and draw a blue it is still 1/6. so you take those two probabilities and multiply them (1/6)*(1/6)=1/36 1*1=1 and 6*6=36.

Your answer is 1/36

7 0

2 years ago

A jet plane can carry up to 200,000 liters of fuel. It used 130,000 liters of fuel during a flight. What percentage of the fuel

-Dominant- [34]

Given:

Capacity of jet plane = 200,000 liters of fuel

Fuel used during flight = 130,000 liters

To find:

The percentage of the fuel capacity it uses on this flight.

Solution:

According to the question, we need to find 130,000 is what percent of 200,000.

$\text{Required percentage}=\dfrac{\text{Fuel used during flight}}{\text{Capacity of jet plane}}\times 100$

$\text{Required percentage}=\dfrac{130000}{200000}\times 100$

$\text{Required percentage}=65$

Therefore, the jet plane uses 65 percent of fuel capacity during flight.

6 0

3 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

Divide 3/16 by 5/2<br> EXPLAIN ANSWER PLZ! AND FAST! I WILL NAME YOU BRANLIEST!

Travka [436]

Use the KCF method to divide

3/6 / 5/2 = 3/6 x 2/5, which equals 1/5

Hope that helps :)

8 0

3 years ago

Read 2 more answers

Line EF is the median of the trapezoid ABCD. The median connects the midpoint of the legs of a trapezoid. Use the diagram to fin

FromTheMoon [43]

Answer:

median: 15
base: 18

Step-by-step explanation:

The median is the average of the lengths of the two bases:

5x -20 = (12 + (4x -10))/2

5x -20 = 2x +1

3x = 21 . . . . . add 20-2x

x = 7

Then the lengths are ...

median = 5x -20 = 5·7 -20 = 15

base = 4x -10 = 4·7 -10 = 18

6 0

3 years ago