We must know that total time ( $t_{T}$ ) that Keenan will be from home is the sum of run ( $t_{R}$ ), hang out ( $t_{H}$ ) and walk times ( $t_{W}$ ), measured in hours:

$t_{T} = t_{R}+t_{H}+t_{W}$

If Keenan runs and walks at constant speed, then equation above can be expanded:

$t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}$

Where:

$x_{R}$ , $x_{W}$ - Run and walk distances, measured in miles.

$v_{R}$ , $v_{W}$ - Run and walk speeds, measured in miles per hour.

Given that $x_{R}=x_{W} = 2.5\,mi$ , $v_{R} = 6\,\frac{mi}{h}$ , $v_{W} = 4\,\frac{mi}{h}$ and $t_{H} = 0.75\,h$ , the total time is:

$t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }$

$t_{T} = 1.792\,h$ ( $1\,h\,48\,m$ )

Kennan will be from home approximately an hour and 48 minutes.

7 0

3 years ago

Write a 3-digit number that can be divided by 3 but not by 10.

NARA [144]

Answer:

999

Step-by-step explanation:

8 0

3 years ago

The students in Ms. Dodd's class recorded the height in feet of palm trees on school property. Their heights were as follows:

dlinn [17]

Answer:

Step-by-step explanation:

8 0

2 years ago