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4 years ago

X^3-64=0 Solve the equation

Mathematics

1 answer:

solniwko [45]4 years ago

8 0

X^3 - 64 = 0

We want to solve for x. Start by getting x by itself on one side.
We can do this by adding 64 to both sides of the equation.

x^3 = 64

Now, to get rid of the 3rd power that x is raised to, we can raise both sides to the 1/3 power

(x^3)^1/3 = 64^1/3

(x^3)^1/3 is the same as x

So x = 64^(1/3) and 64^(1/3) = 4

So x = 4 :)

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An angle measures 10 more than four times a number. It’s supplement is two more than three times the number. What is the measure

kiruha [24]

Answer:

4x +10 + 3x +2 = 180 (since they're supplementary, the angles together =180)

7x +12 =180 (combine like terms on left side, and subtract 12 from both sides)

7x = 168 (divide both sides by 7 to isolate x)

x= 24

angle 1 = 4(24)+10 (plug x into the expression for each angle, and solve)

..................96 +10

angle 1 = 106 degrees (the measure of the first angle)

angle 2 = 3(24) +2

..................72 +2

angle 2 = 74 (the measure of the second angle)

106 +74 =180 (the two add up to 180, so they're supplementary)

Step-by-step explanation:

I hope this helps :)

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3 years ago

Brandon's backpack weighs 3140 grams. brandon

Veronika [31]

Needs more explaining

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3 years ago

Read 2 more answers

What's the answer? It's urgent 4^3 divided by 8 - 1 + 5 divided by 8

posledela

Answer:

42.66666667

Step-by-step explanation:

I did it in my calculator

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3 years ago

Suppose a sample of 972972 tenth graders is drawn. Of the students sampled, 700700 read above the eighth grade level. Using the

max2010maxim [7]

Answer:

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

972 students, 700 read above the eight grade level. We want the confidence interver for the proportion of those who read at or below the 8th grade level. 972 - 700 = 272, so $n = 972, \pi = \frac{272}{972} = 0.28$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.259$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.301$

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

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3 years ago

Why does adding a 0 to the end of a decimal not change the value of the decimal?

aniked [119]

Answer:

because after decimal then value 0 dont have meaning

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3 years ago