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Irina-Kira [14]
3 years ago
6

The public library has volunteers shelve book after they have been returned.lisa shelve 165 book in 25 minutes.patricia shelves

198 books in 45 minutes.How many can Lisa shelve each minute?
Mathematics
1 answer:
uysha [10]3 years ago
8 0

Answer:

Lisa can shelve at least 6 books in 1 minute time.

<u>Explanation:</u>

Given:

The public library has volunteers shelve book after they have been returned.

Lisa shelve 165 book in 25 minutes.

Patricia shelves 198 books in 45 minutes.

To Find:

We have to find how many can Lisa shelve each minute?

Solution:

Now, we know that, number of books she can shelve = \frac{(number of books she shelve in 25 minutes)}{(25 minutes time)}

Number of books she can shelve = \frac{165}{25} = 6.6

Hence, she can shelve at least 6 books in 1 minute time.

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The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

Given expression (x^2-5x+2) and (3x^2+2x+3).

To multiply these equations.

(x^2-5x+2)\times(3x^2+2x+3)

             =x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)

             =(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)

             =3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6

Combine like terms together.

             =3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6

             =3x^4-13x^3-x^2-11x+6

(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6

Hence the answer is 3x^4-13x^3-x^2-11x+6.

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