<em>m Na₂CO₃: 23g×2 + 12g + 16g×3 = 106 g/mol</em>
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1 mol ------- 106g
X ------------ 10,6g
X = 10,6/106
<u>X = 0,1 mol Na₂CO₃</u>
The partial pressure of gas C is 0.902 atm
calculation
partial pressure of gas c =[( percent by volume of gas C / total percent) x total pressure]
percent by volume of gas C= 22%
Total percent = 36% +42% + 22% = 100 %
Total pressure = 4.1 atm
partial pressure of gas C is therefore = 22/100 x 4.1 atm = 0.902 atm
The answer is B. 6CO2+H2O yields C6H12O6+ 6H20.
Answer:
433 m
Explanation:
Since the fall represents motion under gravity, we use the equation
s = ut - 1/2gt² where s = height of cliff or distance bowling ball falls through, u = initial velocity of bowling ball = 0 m/s(since it starts from rest), t = time = 9.4 s and g = acceleration due to gravity = -9.8 m/s².
So, substituting the values of the variables into the equation, we have
s = 0 m/s × 9.4 s - 1/2 × 9.8 m/s² × (9.4 s)²
s = 0 m - 1/2 × -9.8 m/s² × 88.36 s²
s = 1/2(865.928 m)
s = 432.964
s ≅ 433 m
Answer:
3 atoms
Explanation:
2 hydrogen atoms and 1 oxygen atom
