The approximate alcohol content is 210 ml.
Explanation:
It can be deduced from the question that each bottle is of 1000ml or 1 litre.
The first bottle is one half full means it has 500 ml of solution and it has 20% alcohol in it. So volume of alcohol in the solution is
20/100*500
=100 ml
The first bottle is one fifth full, so the volume of mixture is 1/5th of 1000ml
so it is 200ml having 30% alcohol
30/100*200
= 60 ml
The third bottle is one tenth full so its volume is 1/10*1000
100 ml. having 50% of alcohol
50/100*100
50 ml.
The alcohol content obtained from all these 3 litres is:
100+60+50
= 210 ml of alchohol is obtained from 800 ml of mixture.
1) 1 nm = 0.001 µm; one nanometer is equal to 0.001 (10⁻³) micrometer.
d(H) = 10 nm; diameter of hydrogen atom.
d(H) = 10 nm · 0.001 µm/nm.
d(H) = 0.01 µm = 10⁻² µm.
2) 1 nm = 10⁻⁹ m
; one meter is equal to 0.0000000001 (10⁻⁹) meter.
d(H) = 10 nm.
d(H) = 10 nm · 10⁻⁹ m/nm.
d(H) = 0.00000001 m = 10⁻⁸ m.
3) 1 nm = 10⁻⁶ mm
; one nanometer is equal to 0.000001 (10⁻⁶) millimeter.
d(H) = 10 nm · 10⁻⁶ mm/nm.
d(H) = 0.00001 mm = 10⁻⁵ mm.
Answer:
Liters per second is 0.2 LPS
Liters per hour is 720
Explanation:
Divide the litres by the time, than multiply the time of an hour (in seconds) and than multiply the lps by time of an hour in seconds.
Answer: 2.00 V
Explanation:
The balanced redox reaction is:
Here Al undergoes oxidation by loss of electrons, thus act as anode. Copper undergoes reduction by gain of electrons and thus act as cathode.
Where both 
are standard reduction potentials.
![E^0_{[Al^{3+}/Al]}=-1.66V](https://tex.z-dn.net/?f=E%5E0_%7B%5BAl%5E%7B3%2B%7D%2FAl%5D%7D%3D-1.66V)
![E^0_{[Cu^{2+}/Cu]}=0.340V](https://tex.z-dn.net/?f=E%5E0_%7B%5BCu%5E%7B2%2B%7D%2FCu%5D%7D%3D0.340V)
![E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Al^{3+}/Al]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BCu%5E%7B2%2B%7D%2FCu%5D%7D-%20E%5E0_%7B%5BAl%5E%7B3%2B%7D%2FAl%5D%7D)
Thus the standard cell potential is 2.00 V
