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S_A_V [24]
1 year ago
10

Predict the effect (if any) of an increase in temperature on the electrical conductivity of (b) a semiconductor;

Chemistry
1 answer:
attashe74 [19]1 year ago
8 0

If we increase the temperature then the more no of electrons get the energy to jump from conduction band to valence band , thereby increase the conduction of the semiconductor .

Semiconductors :

In the semiconductor the energy gap between the valence band and the conduction band is small . this small energy gap allows some electrons to move from the valence band to the conduction band . thus the semiconductor conduct electricity and conductivity increases with increase in temperature .

There are two type of semiconductor : intrinsic semiconductor and extrinsic semiconductor .

Pure semiconducting substances are called intrinsic semiconductor .

The semiconductor obtained by doping are called extrinsic semiconductors.

Extrinsic semiconductor are of two types : n-type semiconductor and     p-type semiconductor .

n-type semiconductor is due to metal excess defect and p-type semiconductor is due to metal deficiency defect .

Semiconductors are used in transistors , photo-electric devices and rectifiers .

Learn more about semiconductors here :

brainly.com/question/15844033

#SPJ4

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Write the chemical name for MnS2?
Reptile [31]

Answer:

Manganese(II) sulfide

Explanation:

is a chemical compound of manganese and sulfur. It occurs in nature as the mineral alabandite (isometric), rambergite (hexagonal), and recently found browneite (isometric, with sphalerite-type structure, extremely rare, known only from a meteorite).

3 0
2 years ago
Read 2 more answers
What is the hybridization of the central iodine atom in i3−?
Ainat [17]
The central iodine atom in triiodide has sp3d hybridization.In triiodide anion, the central iodine atom has three equatorial lone pairs of electrons and the terminal iodines are bonded axially in a linear shape. Electrons in sp3d hybridization are arranged in trigonal bipyramidal symmetry.
Explanation:

When you draw the Lewis structure of this particle, you'll realize that the central I atom has a pair of bonds and three individual pairs of electrons. as a result of there are five things around that central I atom, it's<span> sp3d hybridized.
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The bonds during a gas<span> (CH4) molecule </span>are fashioned<span> by four separate </span>however<span> equivalent orbitals; </span>one<span> 2s and </span>3<span> 2p orbitals of the carbon </span>interbreed<span> into four sp3 orbitals. </span>within the<span> ammonia molecule (NH3), 2s and 2p orbitals </span>produce<span> four sp3hybrid orbitals, </span>one among that<span> is occupied by a lone </span>try<span> of electrons.</span><span>

</span>
8 0
3 years ago
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Which of the following liquids has the lowest viscosity?
zavuch27 [327]

Answer:

Ether and acetone are the liquids with the lowest viscosities at room temperature.

Explanation:

7 0
3 years ago
Describe how solid liquid and gases particles are arranged
vaieri [72.5K]

Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

5 0
3 years ago
Consider the following intermediate chemical equations. 3 equations. 1: upper C upper H subscript 4 (g) right arrow upper C (s)
ladessa [460]

The enthalpy of the reaction is the amount of energy absorbed or lost in the reaction. The enthalpy of the final reaction  is -113.4 kJ.

<h3>What are intermediate reactions?</h3>

The intermediate reactions are the small reactions that takes place in order to achieve the final reaction product.

The given intermediate reactions are:

\rm CH_4\;\rightarrow\;C\;+\;2\;H_2......\Delta H_1=74. 8\;kJ\\CCl_4\;\rightarrow\;C\;+\;2\;Cl_2......\Delta H_2=95. 7\;kJ\\H_2\;+\;Cl_2\;\rightarrow\;2\;HCl......\Delta H_3=-92. 3\;kJ

The final reaction to be achieved is:

\rm CH_4\;+\;4\;Cl_2\;\rightarrow\;CCl_4\;+\;4\;HCl

The second reaction is reversed in order to achieve the final reaction product.

The enthalpy of the final reaction (\Delta H_{rxn}) is given as:

\Delta H_{rxn}=\Delta H_1-\Delta H_2+\Delta H_3

Substituting the values of enthalpy:

\Delta H_{rxn}= 74. 8-95. 7+(-92. 3)\text k\text J\\\Delta H_{rxn}=-113.4\;\rm kJ

The final enthalpy of the reaction is -113.4 kJ. Thus, option B is correct.

Learn more about enthalpy of reaction, here:

brainly.com/question/1657608

4 0
2 years ago
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