After a reflection across line y=x the vertices of triangle P’Q’R’ are as follows
P’= (-1,-7)
Q’= (-8-7)
R’= (-3,3)
Answer:
1) 
2) 
3) 
4) 
5) 
6) 
Step-by-step explanation:
1) 





2) 





3) 




4) 




5) 




6) 




Answer: a = 4
Step-by-step explanation: Area of a triangle is calculated as:
.
The triangle formed by the parabola has base (b) equal to the distance between the points where the graph touches x-axis and height (h) is the point where graph touches the y-axis.
The points on the x-axis are the roots of the quadratic equation:
a(x-3)(x+2)=0
(x-3)(x+2)=0
x - 3 = 0
x = 3
or
x + 2 = 0
x = -2
So, base is the distance between (-2,0) and (3,0).
Since they are in the same coordinate, distance will be:
b = 3 - (-2)
b = 5
Area of the triangle is 10. So constant a is

5a = 10.2
a = 4
The constant a of the function y = a(x-3)(x+2) is 4.
Add these together.
You get -15y=-45
So y=3
Now plug in to first equation.
8x-8(3)=-16
8x-24=-16
8x=8 so x=1
Check both values in second equation.
-8(1)-7(3)=
-8-21=-29
It works...so x=1, y=3