Answer:
The correct answer is A.) Sister chromatids are pulled apart.
Explanation:
This is because during Anaphase II in Meiosis, the sister chromatids are pulled apart.
Chromosome pairs line up during Prophase I. <em>Not B.</em> When the chromosome pairs pair up this is also Metaphase I. <em>Not C.</em> When chromosome pairs are pulled apart, Anaphase I is occurring.
Hope this helps,
♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
The 'D' in DNA stands for deoxyribose.
Answer:
D. Cell wall
Explanation:
Cell wall is also present in prokaryotes it is made of peptidoglycan layer.
