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Degger [83]
3 years ago
7

I need help one this question how do you Factor 75 - 95.

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

+-(1,2,4,5,10,20)

Step-by-step explanation:

well if this is factors of -20 (bc 75-95=-20)

then it will be +-(1,2,4,5,10,20)

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Points are usually labeled as:
Alex73 [517]

Answer: a capital letter

Explanation: The most basic figure in geometry is called a point.

For example, ·A or ·Q.

Notice that above, points are usually labeled with a capital letter.

8 0
3 years ago
Plz find c) arc XYR thank you
Butoxors [25]
XYR=36 hope this helps I actually don't know if it is right so I'm so sry if it is wrong so sry
4 0
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Solve this system and list the method that you chose graphing substitution or elimination Y=2x-12
zmey [24]
Substitution

y = 2x - 12
y = -x + 3

-x + 3 = 2x - 12
+ x + x
-----------------------------
3 = 3x - 12
+ 12 + 12
-----------------------
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------ ------
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The final answer is (5,-2).
8 0
2 years ago
AJ is the bisector of ∠HJI. Determine the value of x.
atroni [7]

Answer:

C

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8 0
3 years ago
Researchers have found that after 25 years of age the average size of the pupil in a
laila [671]

Answer:

At 25 = 6.8612mm

At 50 years = 5.422mm

Step-by-step explanation:

Equation,

d = 2.115Logₑa + 13.669

d = diameter of the pupil

a = number of years

Note : Logₑa = In a (check logarithmic rule)

d = 2.115Ina + 13.669

1. At 25 years,

d = -2.115In25 + 13.669

d = -2.115 × 3.2188 + 13.669

d = -6.807762 + 13.669

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At 25 years, the pupil shrinks by 6.86mm

2. At 50 years,

d = -2.1158In50 + 13.669

d = -2.1158 * 3.912 + 13.669

d = -8.2770 + 13.699

d = 5.422mm

At 50 years, the pupil shirks by 5.422mm

To save this question, I had to plug in the values into the equation.

Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.

8 0
3 years ago
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