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sladkih [1.3K]
3 years ago
10

The ratio of the volume of two cubes is 216 to 64. What is the ratio of their surface/

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0
The volume of a cube is V=s^3, so s=V^(1/3).

The area of a cube is A=6s^2, using s found above we have:

A=6(V^(2/3))

Let V and S be the volume and area of the larger and v and s be the volume and area of the smaller cube.

A:a

6(V^(2/3)):6(v^(2/3))

V^(2/3):v^(2/3), we are given that V=216 and v=64 so

216^(2/3):64^(2/3)

36:16

9:4


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Ubi made a banana cream pie.His brother ate 1/3 of the pie and his sister ate 2/6 of the pie.
tamaranim1 [39]
2/3 of the pie had been eaten, there is 1/3 left
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How do you solve 9| x+8 | + 10 < 55 & how is it graphed
mafiozo [28]
Hello!

First, let's write the problem.
9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55
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9\left|x+8\right|+10-10\ \textless \ 55-10
9\left|x+8\right|\ \textless \ 45
Divide both sides by 9.
\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}
\left|x+8\right|\ \textless \ 5
When we got absolute value, we are going to get two results.
x+8\ \textless \ 5
and
x+8\ \textgreater \ -5

Let's solve the first one,
x+8\ \textless \ 5x+8\ \textless \ 5
Subtract 8 from both sides.
x+8-8\ \textless \ 5-8
x\ \textless \ -3x\ \textless \ -3

Let's solve the second one.
x+8\ \textgreater \ -5
Subtract 8 from both sides.
x+8-8\ \textgreater \ -5-8
x\ \textgreater \ -13x\ \textgreater \ -13

Let's combine the ranges.
-13\ \textless \ x\ \textless \ -3

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

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3 years ago
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AlladinOne [14]

The answer is 4/15

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In other words, two fifths times two thirds equals four fifteenths.

Learn more about fraction here:

brainly.com/question/17220365

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