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insens350 [35]
2 years ago
9

Need help on this one question please

Mathematics
1 answer:
Elan Coil [88]2 years ago
6 0
P(x, y) Q(x,y)
P(-2, -1) start at 0. Go to the left two squares, then go down 1 square. mark a point there
Q(2, 4) start at 0. Go to the right two squares, go up 4 squares. mark a point there.
connect two points
make a right triangle
Then use the pythereom 
4^{2} + 5^{2} = (PQ)^{2}
41 = (PQ)^{2}
\sqrt{41}  = PQ

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LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

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Right Hand Limit

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LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

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