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spin [16.1K]
3 years ago
5

Drag the tiles to the correct boxes to complete the pairs. Match each inequality to the number line that represents its solution

. x – 99 ≤ -104 x – 51 ≤ -43 150 + x ≤ 144 75 < 69 – x

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

The four answers in the attached figure

Step-by-step explanation:

Part 1) we have

x-99\leq-104

Solve for x

Adds 99 both sides

x-99+99\leq-104+99

x\leq-5

The solution is the interval ----> (-∞, -5]

All real numbers less than or equal to -5

In a number line, the shaded area at  left of x=-5 (close circle)

Part 2) we have

x-51\leq-43

Solve for x

Adds 51 both sides

x-51+51\leq-43+51

x\leq 8

The solution is the interval ----> (-∞, 8]

All real numbers less than or equal to 8

In a number line, the shaded area at  left of x=8 (close circle)

Part 3) we have

150+x\leq144

Solve for x

Subtract  150 both sides

150+x-150\leq144-150

x\leq -6

The solution is the interval ----> (-∞, -6]

All real numbers less than or equal to -6

In a number line, the shaded area at  left of x=-6 (close circle)

Part 4) we have

75

Solve for x

Subtract 69 both sides

75-69

6

Multiply by -1 both sides

-6> x

Rewrite

x < -6

The solution is the interval ----> (-∞, -6)

All real numbers less than -6

In a number line, the shaded area at  left of x=-6 (open circle)

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Find the number if: 4.5% of it is 23% of 45
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Well, let's say the number is "x", so "x" is the 100%.

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if we take 45 to be the 100%, what is its 23%?

\bf \begin{array}{ccll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;45&100\\&#10;a&23&#10;\end{array}\implies \cfrac{45}{a}=\cfrac{100}{23}\implies \cfrac{45\cdot 23}{100}=a\implies 10.35=a

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