All categories

3 years ago

Factor completely. x 3 + 6x 2 - 4x - 24

Mathematics

1 answer:

Ulleksa [173]3 years ago

5 0

You can factor (x^3 and 6x^2) and (-4x and -24).

So x^2(x+6) - 4(x+6)

(x^2-4)(x+6)

(x-2)(x+2)(x+6)

You might be interested in

Tom wishes to purchase a property that has been valued at $300,000. He has $30,000 available as a deposit, and will require a mo

Mekhanik [1.2K]

Answer: The total interest paid on the mortgage is $179550

Step-by-step explanation:

The initial cost of the property is $300000. If he deposits $30000, the remaining amount would be

300000 - 30000 = $270000

Since the remaining amount was compounded, we would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 270000

r = 2% = 2/100 = 0.02

n = 12 because it was compounded 12 times in a year.

t = 25 years

Therefore,

A = 270000(1+0.02/12)^12 × 25

A = 270000(1+0.0017)^300

A = 270000(1.0017)^300

A = $449550

The total interest paid on the mortgage is

449550 - 270000 = $179550

3 0

3 years ago

You are shopping for T-shirts. Clothing Warehouse sells 3 T-shirts for $52. The Scene sells 2 T-shirts for $83. New Threads sell

Pepsi [2]

The 3 for $52 each shirt is 17.33

5 0

3 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$