I need help with a question in algebra 2. May you please help me? If that’s fine with you?
Answer: 1.4
Step-by-step explanation:
To calculate the grade point average you have to sum all the points of each course multiplying the hours and then diveded by the total number of hours she did.
She earned a grade B in her 4 hour topology course, so she has 3*4 points.
In her 11 hour gouvernment course, she earned a grade D, so she has 1*11 points. In the 2 hour biology course she earned a grade D, so she has 1*2 points and in her 3 hours studio art course she had also a grade D, so she has 1*3 points
She has done 3+2+11+4 hours of subjects=20.
The total average is (3*4+1*11+1*2+1*3)/20=28/20=1.4
Answer:
66%
Step-by-step explanation:
Given :
Age Percentile
75 97
65 90
55 78
45 58
35 37
25 13
20 66
To Find :The percentage of drivers who are younger than 20 is _____%.
Solution:
Refer the given table
The percentile corresponding to age 20 is 66.
Percentile : A data item is said to be in nth percentile of distribution if n% of the distribution are less than that particular data item.
So, drivers who are younger than 20 are said to be in 66 percentile if 66%of the distribution are less than that particular data item.
Hence The percentage of drivers who are younger than 20 is 66%.
Answer:
The answer is 150
Step-by-step explanation:
I think what you mean with the numbers between the "I's" is <em>absolute value</em>. Any number is just that number, so the <em>absolute value </em>of -6, is 6. The absolute value of 24 is 24. That means it's simply 137+13, which is <u>150</u>.
Answer:
a. 720
b. 0.3
Step-by-step explanation:
a.
Three balls are selected at random without replacement.
First ball can be selected in 10 ways
Second ball can be selected in 9 ways
Third ball can be selected in 8 ways
Thus, there are 10×9×8 =720 different ways of selecting three balls.
b.
There are three cases that satisfy this condition
- first ball picked is 5, the others are not
- first ball is not 5, second is 5, third is not
- first and second ball is not five, third ball is 5
Each probabilities are:
![\frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%2A%20%5Cfrac%7B9%7D%7B9%7D%20%2A%5Cfrac%7B8%7D%7B8%7D%20%3D%5Cfrac%7B1%7D%7B10%7D)
![\frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%7D%20%2A%5Cfrac%7B1%7D%7B9%7D%20%2A%5Cfrac%7B8%7D%7B8%7D%20%3D%5Cfrac%7B1%7D%7B10%7D)
![\frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%7D%20%2A%5Cfrac%7B8%7D%7B9%7D%20%2A%5Cfrac%7B1%7D%7B8%7D%20%3D%5Cfrac%7B1%7D%7B10%7D)
Thus, one of the balls selected is the number 5 is then ![\frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%2B%20%5Cfrac%7B1%7D%7B10%7D%20%2B%20%5Cfrac%7B1%7D%7B10%7D%20%3D%20%5Cfrac%7B3%7D%7B10%7D)