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maks197457 [2]
3 years ago
8

Can someone help me please and quickly because I’m being timed! Thanks!

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

Answer:

That would be 180

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What is the z-score of a newborn who weighs 4,000 g?.
vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

X \sim N(\mu, \sigma)

(X is following normal distribution with mean \mu and standard deviation  \sigma)

then it can be converted to standard normal distribution as

Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

P(Z \leq z) = P(Z < z) )

Also, know that if we look for Z = z in z tables, the p value we get is

P(Z \leq z) = \rm p \: value

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

  • X = weights of newborns for some considered system (in grams)
  • \mu = mean weight of newborns (in grams)
  • \sigma = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}

Thus, the z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

Learn more about z-scores here:

brainly.com/question/13299273

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2 years ago
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nignag [31]
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6 0
3 years ago
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IgorLugansk [536]
I would say the answer is E. The coach cannot select those he observes. the reason being is because all people can run a different time due to the age of the person, not saying that they have a limit but the question leaves out how fit the player is. to put in words a athletic person on the average could run about 4-5 laps depending on how far each lap is. Hope that helps
5 0
3 years ago
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