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pickupchik [31]
3 years ago
15

If $125 is invested at an interest rate of 18% per year and is compounded continuously, how much will the investment be worth in

2 years?
Use the continuous compound interest formula A = Per
$123
Mathematics
1 answer:
kramer3 years ago
5 0

Answer:

I think it would be 170$

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Points P. Q. and S are on a circle. The measure of arc PQ is 58°<br>What is the measure of arc PSQ?​
Lisa [10]

Answer:

<h2>The arc PSQ is 302°.</h2>

Step-by-step explanation:

We know that the total length of the circumference is 360°. In this case, that total is divide in two arcs PQ and PSQ, so

PQ+PSQ=360\°

Replacing given values, we have

PSQ=360-58=302\°

Therefore, the arc PSQ is 302°.

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PLEASE HELP<br><br> Solve: 3 square root x^2-8=2
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Answer:

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Step-by-step explanation:

IF your equation looks like this :

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Read 2 more answers
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
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