F hope it helps have a good day byeee
The answer you chose is indeed correct!
Vertex form of a quadratic is y = a(x - h)^2 + k.
( h , k ) is the vertex and in the problem the very is ( 1, -3) so plug that in and:
y = (x - 1 )^2 + (-3) this is equal to:
y = (x -1)^ 2 - 3
hope this helps c:
You find the range by plugging 0 ,2 and 4 into x^2 + 1.
for x = 0 y = 0 + 1 = 1
x = 2, y = 2^2 + 1 = 5
x = 4 y = 4^2 + 1 = 17
so the range is {1, 5, 17}
Answer: 
Step-by-step explanation:
The answer is: 64
Hope it helps! And have a great day✌