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2 years ago

Evaluate the expression 4.02 + 3y for x = 5 and y = 6

Mathematics

1 answer:

IgorC [24]2 years ago

6 0

the expression looks like its missing the x value tbh...

you provided x and y but the expression doesn't

have an x.

so, that applied, 4.02+3(6)

4.02+3(6)

4.02+18

22.02

------------------

but.... if you wrote your expression wrong and you meant to write 4.02x+3y,

than:

4.02(5) + 3(6)

20.1+18

= 38.1

__________

So, if you actually meant 4.02 + 3y, ur answer would be 22.02, but if you meant 4.02x+3y, then your answer would be 38.1

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3 years ago

A local company makes a candy that is supposed to weigh 1.00 ounces. A random sample of 25 pieces of candy produces a mean of 0.

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Answer:

$n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107$

So the answer for this case would be n=107 rounded up to the nearest integer

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Information given

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$s=0.004$ the sample deviation

$n =25$ the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

We can use as estimator of the real population deviation the sample deviation for this case $\hat \sigma = s$ / The critical value for 99% of confidence interval is given by $z_{\alpha/2}=2.58$ , replacing into formula (b) we got:

$n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107$

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3 years ago

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Answer:

what is the question above what you are showing in the picture ?

Step-by-step explanation:

it will help a lot

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3 years ago

Read 2 more answers

Evaluate the expression 4.02 + 3y for x = 5 and y = 6​

Evaluate the expression 4.02 + 3y for x = 5 and y = 6