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WARRIOR [948]
3 years ago
10

You work two jobs. You earn $14.64 per hour as a salesperson and $12.20 per hour stocking shelves. Your combined earnings this m

onth are $219.60. Let x represent the number of hours worked stocking shelves and let y represent the number of hours worked in sales. Graph the equation that models this situation.
Mathematics
1 answer:
Igoryamba3 years ago
7 0

I'm assuming you have to graph a line that shows the combination of earnings.

Our equation is 14.64y + 12.20x = 219.60

We'll be solving for x and y. We'll need to substitute the variables, one at a time, to 0, in order to find their intercepts.

Let's do x first.

14.64(0) + 12.20x = 219.60

12.20x = 219.60

Divide by 12.20 on both sides.

x = 18

Now let's solve for y.

14.46y + 12.20(0) = 219.60

14.46y = 219.60

Divide both sides by 14.46.

y = 15.18

That is actually a long decmal, but since we're dealing with money, we round it down to the nearest cent.

So, now we know x = 18 and y = 15.18.

Graph those on the x coordinate plane and the y coordinate plane, and make a line connecting the two. That line represents all the solutions.

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3 0
3 years ago
Read 2 more answers
1) Find an equation of the tangent line at each given point on the curve.x = t2 − 4, y = t2 − 2tat (0, 0)at (−3, −1)at (−3, 3)2)
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Answer:

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2) DNE ( does not exist )

Step-by-step explanation:

The general equation of tangent line

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attached below is the detailed solution on how i derived the answers above

8 0
3 years ago
Lateral erea of cube​
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Answer:

4a2

Step-by-step explanation:

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4 0
2 years ago
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Nitrates are groundwater contaminants derived from fertilizer, septic tank seepage and other sewage. Nitrate poisoning is partic
o-na [289]

Answer:

a) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

b) n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

Part a

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior information about the population proportion we can use ase estimator \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

Part b

For thi case the estimator for p is \hat p =0.07

n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

4 0
3 years ago
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