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vesna_86 [32]
3 years ago
10

Need help with question 3, 8, 13, 15, 17, 18

Mathematics
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

18. 8x+40

8. 2hours 30 minutes

Step-by-step explanation:

8. 8x2= 16

8 divided by 2 is 4

4+16= 20

4mph = 30 minutes

8mph = 1 hour

8+8+4= 2 hours and 30 minutes

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Which variable expression represents the phrase the product of h and p
lutik1710 [3]

Answer:

hp

Step-by-step explanation:

Here, we want to write the variable expression representing the product of h and p

Mathematically, what we just have to do here is multiply h by p

That will be;

h * p = hp

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Mapping diagram: Is it a function? (yes /<br> no<br> ) Why or why not?
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2 years ago
Find the exact value of : cos(2 arctan(4/3))
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A band leader wants to line up 236 band members in 4 rows so that each row has 2 members more than the row before. How many band
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Read 2 more answers
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
3 years ago
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