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2 years ago

An equation is shown below 1/2X+3/2=2^x what is the solution to the equation? A x=1. B x=2. C x=4 . D x = 8

Mathematics

1 answer:

fredd [130]2 years ago

4 0

Answer:

a x=1

explanation:

i got it right on my test today

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What is a formula for the nth term of the given sequence?

lakkis [162]

Answer: option D is the correct answer.

Step-by-step explanation:

The given sequence is a geometric sequence because the consecutive terms differ by a common ratio.

The formula for determining the nth term of a geometric progression is expressed as

an = a1r^(n - 1)

Where

a1 represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a1 = 36

r = 12/36 = 4/12 = 1/3

Therefore, the formula for the nth term of the sequence is

an = 36 × 1/3^(n - 1)

an = 36 × 3^-1(n - 1)

an = 36 × 3^(-n + 1)

an = 36 × 3^(1 - n)

6 0

3 years ago

Calculate the average rate of change of f(x) = 1 x - x2 - 2 for 3 ≤ x ≤ 6. A) -163 18 B) -18 163 C) 163 18 D) 18 163

larisa86 [58]

To solve this we are going to use the average rate of change formula: $A(x)= \frac{f(b)-f(a)}{b-a}$
where
$A(x)$ is the average rate of change of the function
$f(a)$ is the position function evaluated at $a$
$f(b)$ is the position function evaluated at $b$
$a$ is the first point in the interval
$b$ is the second point in the interval

We can infer for our problem that the first point is 3 and the second point is 6, so $a=3$ and $b=6$ . Lets replace those values in our formula:
$A(x)= \frac{f(b)-f(a)}{b-a}$
$A(x)= \frac{f(6)-f(3)}{6-3}$
$A(x)= \frac{6-6^2-2-(3-3^2-2)}{3}$
$A(x)= \frac{-32-(-8)}{3}$
$A(x)= \frac{-32+8}{3}$
$A(x)= \frac{-24}{3}$
$A(x)=-8$

We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>

3 0

3 years ago

Read 2 more answers

Plz help

Sergio039 [100]

2(5*4)+2(4*3)+2(3*5)=94 sq.m (Orginial SA)
2(4*5)+2(5*6)+2(6*4)=148 sq.m (Total SA)

148-94=54 (New SA)

4 0

2 years ago

Read 2 more answers

In a right triangle, a and b are the lengths of the legs and c is the length of the hypotenuse. if a=7 feet and b=7 feet, what i

V125BC [204]

The length of hypotenuse when the value of legs of a right angled triangle are 7 and 7 feet is 9.9 feet.

Given that a and b are legs and c is the hypotenuse. length of legs of a right angled triangle are 7 feet and 7 feet.

We have to find the value of c in the right angled triangle.

In this we have to apply pythagoras theorem because it says tat the square of hypotenuse is equal to the sum of squares of base and perpendicular of that right angled triangle.

$H^{2} =P^{2} +B^{2}$