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aivan3 [116]
3 years ago
8

Does the trapizoid have at lease 1 pair of parallel sides

Mathematics
2 answers:
Artyom0805 [142]3 years ago
4 0
All trapezoid has 1 parallel line on the opposite side so I suggest that it does have a pair of parallel sides. I Hope I HELPED YOU :D
mezya [45]3 years ago
3 0
All tapezoids have 1 parallel side
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Multiplication Property of Equality---- If 6x divided by 8 = 40, then______
NNADVOKAT [17]

Answer:

Option C.) 6x=320

Step-by-step explanation:

we know that

The <u>Multiplication Property of Equality</u> states that if you multiply both sides of an equation by the same number, the sides remain equal

we have

\frac{6x}{8}=40

Apply the multiplication property of equality

Multiply by 8 both sides

\frac{6x}{8}(8)=40(8)

6x=320

therefore

The answer is the Option C

6 0
3 years ago
Read 2 more answers
-9(m+3) +14=-49 please show work
yKpoI14uk [10]

Answer:

m=4

Step-by-step explanation:

−9(m+3)+14=−49

Step 1: Simplify both sides of the equation.

−9(m+3)+14=−49

(−9)(m)+(−9)(3)+14=−49(Distribute)

−9m+−27+14=−49

(−9m)+(−27+14)=−49(Combine Like Terms)

−9m+−13=−49

−9m−13=−49

Step 2: Add 13 to both sides.

−9m−13+13=−49+13

−9m=−36

Step 3: Divide both sides by -9.

−9m

−9

=

−36

−9

m=4

8 0
3 years ago
PLease help ill give brainliest
stepan [7]

A bar graph is when you want to compare the data in the data set (which this data set does)

A line graph is used when the data set creates a straight line (which this data set does not)

A circle graph (also known as a pie chart) is used when the data set measures percentages that will total 100% (which this data set does not)

A stem plot is used when you want to show the frequency of the beginning digit <em>or digits</em> (which this data set does not)

Answer: A

3 0
3 years ago
Help please? its an exam
Nikolay [14]

Answer:

TU=4

Step-by-step explanation:

WU cuts the triangle in half (hint- angleTUW=90°)

so VU=TU

therefore, TU=4

5 0
3 years ago
6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0
3 years ago
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