Answer:
The average rate of change is 4.
Step-by-step explanation:
It is 4 because when you do the formula to find the rate of change it comes out to be 4.
Answer:
The equation for rational function for given asymptotes is
f(x)=(-4x^2-6)/{(x-3)(x+3)}
Step-by-step explanation:
Given:
vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at
y=-4 i.e parallel to x axis.
To find:
equation of a rational function i.e function in form p/q
Solution;
the equation should be in form of p/q
Numerator :denominator.
Consider f(x)=g(x)/h(x)
as vertical asymptote are x=-3 and x=3
denominator becomes, (x-3) and (x+3)
for horizontal asymptote to exist there should have same degrees in numerator and denominator which of '2'
when g(x) will be degree '2' with -4 as coefficient and dont have any real.
zero.
By horizontal asymptote will be (-4x^2 -6)
The rational function is given by
f(x)=g(x)/h(x)
={(-4x^2-6)/(x-3)(x+3)}.
Answer:
14
Step-by-step explanation:
70
1 * 70
5 * 14
7 * 10
42
1 * 42
3 * 14
7 * 6
28
1 * 28
2 * 14
7 * 4
pick the largest factor from 70 and check it they also work with the other two. 14 is the GCF.
With the mean and range, we can estimate the weights of the smallest and largest animals in each group.
For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]
<h3>
Which conclusions can be made with the given information?</h3>
We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.
- From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
- And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg
(Assuming a normal distribution).
Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:
- The largest dog weights 32kg + 45kg/2 = 54.5kg
- The smallest dog weights 32kg - 45kg/2 = 9.5kg
(again, assuming a normal distribution).
If you want to learn more about means and ranges:
brainly.com/question/14532771
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