Point P is the orthocenter of the triangle.
Answer:
y=1/3 + 3
Step-by-step explanation:
y= 1/3x + b
(1) = 1/3(-6) + b
1 = -2 +b
3 = b
y=1/3 + b
Step-by-step explanation:
step 1. 12x - 15 - 12x = 7x + 20
step 2. 12x - 12x - 15 = 7x + 20 (grouping of terms)
step 3. -15 = 7x + 20 (adding like terms)
step 4. -35 = 7x (subtract 20 from both sides)
step 5. this step is incorrect.
step 6. -5 = x ( divide both sides by 7)
step 7. x = -5 (put the variable first).
Answer:
option B
3
Step-by-step explanation:
Given in the question an expression
Whole numbers are positive numbers, including zero, without any decimal or fractional parts.
Possible range of domain will be 1 ≤ x ≤ 48
We know that perfect square between 1 and 48 are
1 , 4 , 16 , 25 , 36
1)
x = 3
√48/3 = √16 = 4
2)
x = 12
√48/12 = √4 = 2
3)
x = 48
√48/48 = √1 = 1
X=2h, y=3k
Substitute these values into equations.
y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4
2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1
We have a system of equations now.
3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1
2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0
4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0
(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0
Denominator cannot be = 0
4h(2-2h)≠0
Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1
Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.
h=3/4, then 3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then 3k = 4-4*(-1) =8 , 3k=8, k=8/3
So,
if h=3/4, then k=1/3,
and if h=-1, then k=8/3 .
