1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmasim [6.3K]
3 years ago
9

Attached is the question

Mathematics
1 answer:
Verizon [17]3 years ago
4 0
There id nothing shown for us to answer
You might be interested in
Mystery Boxes: Breakout Rooms
ollegr [7]

Answer:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

Step-by-step explanation:

Given

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}

Required

Fill in the box

From the question, the range is:

Range = 60

Range is calculated as:

Range =  Highest - Least

From the box, we have:

Least = 1

So:

60 = Highest  - 1

Highest = 60 +1

Highest = 61

The box, becomes:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question:

IQR = 20 --- interquartile range

This is calculated as:

IQR = Q_3 - Q_1

Q_3 is the median of the upper half while Q_1 is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}

<u>Upper half</u>

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

The quartile is calculated by calculating the median for each of the above halves is calculated as:

Median = \frac{N + 1}{2}th

Where N = 7

So, we have:

Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th

So,

Q_3 = 4th item of the upper halves

Q_1= 4th item of the lower halves

From the upper halves

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

<u></u>

We have:

Q_3 = 32

Q_1 can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

IQR = Q_3 - Q_1

Where Q_3 = 32 and IQR = 20

So:

20 = 32 - Q_1

Q_1 = 32 - 20

Q_1 = 12

So, the lower half becomes:

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}

From this, the updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question, the median is:

Median = 22 and N = 14

To calculate the median, we make use of:

Median = \frac{N + 1}{2}th

Median = \frac{14 + 1}{2}th

Median = \frac{15}{2}th

Median = 7.5th

This means that, the median is the average of the 7th and 8th items.

The 7th and 8th items are blanks.

However, from the question; the mode is:

Mode = 18

Since the values of the box are in increasing order and the average of 18 and 18 do not equal 22 (i.e. the median), then the 7th item is:

7th = 18

The 8th item is calculated as thus:

Median = \frac{1}{2}(7th + 8th)

22= \frac{1}{2}(18 + 8th)

Multiply through by 2

44 = 18 + 8th

8th = 44 - 18

8th = 26

The updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question.

Mean = 26

Mean is calculated as:

Mean = \frac{\sum x}{n}

So, we have:

26= \frac{1 + 2nd + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 12th + 58 + 61}{14}

Collect like terms

26= \frac{ 2nd + 12th+1 + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 58 + 61}{14}

26= \frac{ 2nd + 12th+304}{14}

Multiply through by 14

14 * 26= 2nd + 12th+304

364= 2nd + 12th+304

This gives:

2nd + 12th = 364 - 304

2nd + 12th = 60

From the updated box,

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

We know that:

<em>The 2nd value can only be either 2 or 3</em>

<em>The 12th value can take any of the range 33 to 57</em>

Of these values, the only possible values of 2nd and 12th that give a sum of 60 are:

2nd = 3

12th = 57

i.e.

2nd + 12th = 60

3 + 57 = 60

So, the complete box is:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

6 0
2 years ago
What is the volume of this cylinder?
dalvyx [7]

Answer:

12762.72 cubic meters

Step-by-step explanation:

The volume of a cylinder is denoted by the formula: V=\pi r^{2} h, where r is the radius and h is the height.

Here, we see that the height h = 11.5 m. We also see that the diameter is 37.6 meters. Since diameter = 2 * radius, we can divide this number by 2 to get the radius: r = 37.6/2 = 18.8 meters.

Now substitute these values into the equation:

V=\pi *(18.8^2)*11.5=3.14*(18.8^2)*11.5=12762.72 cubic meters

Hope this helps!

5 0
3 years ago
Read 2 more answers
At the beginning of six grade Kevin was 4’10” tall. at the end of ninth-grade he was 5’9” tall. what was the percentage of incre
tankabanditka [31]

Answer:

<u>Kevin's height increased 19.05%</u>

Step-by-step explanation:

Height of Kevin at the beginning of sixth grade = 4’10”

Height of Kevin at the end of ninth grade = 5’9”

What was the percentage of increase in Kevin height?

For answering this question, we should convert Kevin's heights to decimal number, this way:

1 feet = 12 inches

4’10” = 4 10/12 = 4.83

5’9” = 5 9/12 = 5.75

Now, let's use the Direct Rule of Three:

Height     Percentage

4.83              100

5.75                 x

***********************************

4.83x = 5.75 * 100

4.83x = 575

x = 575/4.83

x = 119.05

119.05 - 100 = 19.05

<u>Kevin's height increased 19.05%</u>

8 0
3 years ago
If m∠Y = 107° and m∠Z = 33°, what is m∠X?
yawa3891 [41]

Answer:

B would be the answer.

Step-by-step explanation:

Use what they said. All angles in a triangle would sum to 180 degrees.

So based on that, 107 + 33 + <x = 180

140 + <x = 180

<x would then be 40 degrees

8 0
2 years ago
How to do (4x10^3) + (4x10^4)?
Ivan
Solution:
4 \times 10 {}^{3 }  = 4 \times 1000 = 4000 \\ 4 \times 10 {}^{4}  = 4 \times 10000 = 40000 \\ 4000 + 40000 = 44000
3 0
3 years ago
Read 2 more answers
Other questions:
  • Can someone help me do this I'm not good at this kind of math
    8·1 answer
  • If 3a-2b= 8 and a+3b=7 what is the value of 4a+b?
    6·1 answer
  • A 40 meter ladder makes an angle of 32° with the playground. How far is the bottom of the ladder from the base of the playground
    7·1 answer
  • A circular crop field has an irrigation system in which a pipe, with one end attached to a tower at the center of the field, tur
    10·1 answer
  • Im stuck on this question..​
    8·1 answer
  • Janelle practices basketball every afternoon in her driveway. Each day, her goal is to make 4 more baskets than she made the day
    8·2 answers
  • Part B:
    15·1 answer
  • What is the reciprocal of 2 1/2
    6·2 answers
  • 6+4-(4x2)+22^3=?? Can someone help!
    9·1 answer
  • Y=-1,X+2y=9 solve by substitution show all work
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!