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4 years ago

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Verizon [17]4 years ago

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Which trigonometric functions are negative in the fourth (IV) quadrant?

anzhelika [568]

<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

Explanation:

On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.

Since sine is negative, so is cosecant as this is the reciprocal of sine

csc = 1/sin

In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.

Because tangent is negative, so is cotangent.

The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.

7 0

3 years ago

there are 25 students in mrs. venetozzi’s class at the beginning of the school year, and the average number of siblings for each

kompoz [17]

So, at the beginning there are a total of 25*3=75 siblings (we can assume that each of them had exactly 3 siblings, that's what average means; that we can assume this).

Now we have 25+1=26 students and the number of siblings is 75+8=83

and the average is $\frac{83}{26}= 3.192$ , and rounded it's 3.19.

5 0

3 years ago

What is the slope of this equation 1/2x - 1/3

viktelen [127]

It is not linear, so therefore no slope

5 0

3 years ago

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please help. answer is 62.1m(squared) and the objects are composite! please show the work, no matter what i do i cant seem to ge

yuradex [85]

Answer:

$SA=62.1\ m^2$

Step-by-step explanation:

step 1

Find the surface area of the smaller rectangular prism

$SA=2B+Ph$

where

B is the area of the base

P is the perimeter of the base

h is the height of the prism

$SA=2[(2.5)(1.5)]+2(2.5+1.5)(1.5)$

$SA=7.5+12=19.5\ m^2$

step 2

Find the surface area of the cube

$SA=6s^2$

where

s is the length side of the cube

$SA=6(2.5^2)=37.5\ m^2$

step 3

Find the lateral area of the cylinder

$LA=\pi DL$

where

D is the diameter of the base

L is the length of cylinder

$LA=(3.14)(0.5)(3.5)=5.495\ m^2$

step 4

Find the area of the base of cylinder

$A=\pi r^{2}$

we have

$r=0.5/2=0.25\ m$ ----> the radius is half the diameter

$A=(3.14)(0.25)^{2}=0.19625\ m^2$

step 5

Find the surface are of the composite figure

we know that

The surface area of the composite figure is equal to the surface area of the smaller rectangular prism plus the lateral area of the cylinder, plus the surface area of the cube, minus the area of the two bases of cylinder

$SA=19.5+5.495+37.5-2(0.19625)=62.1\ m^2$

5 0

3 years ago

Factor completely. n ^4 - 1

inna [77]

(n^4 - 1) = (n^2 - 1) (n^2 +1) = (n - 1) (n + 1) (n^2 + 1)

8 0

4 years ago

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