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3 years ago

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Mathematics

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Verizon [17]3 years ago

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Do i pee or poop before my test, (i can only do one). :(

Oksana_A [137]

Answer:

Poop

Step-by-step explanation:

People might not be able to see the poop through your pants, but pee will be very noticeable.

4 0

3 years ago

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2-2x2-(39 divided by 1)+2+9

artcher [175]

-30 is the answer for your question

6 0

3 years ago

The slope of the the tangent line to a curve at a point. Calc derivative help

pickupchik [31]

Answer:

y = 108x + 216

Step-by-step explanation:

given

y = 4x³ then $\frac{dy}{dx}$ = 12x² = $m_{tgt}$

x = 3 ⇒ m = 12(- 3)² = 108

equation of tangent in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept ), hence

y = 108x + b

To find b substitute (- 3, - 108) into the equation

- 108 = -324 + b ⇒ b = - 108 + 324 = 216

y = 108x + 216 ← equation of tangent

5 0

3 years ago

While sailing toward a statue, a sailor in a boat observed that at a certain point, the angle of elevation of the tip of the t

sveta [45]

Answer:

The answer is on this link:

https://www.slader.com/discussion/question/while-sailing-toward-the-statue-of-liberty-a-sailor-in-a-boat-observed-that-at-a-certain-point-the-a/

7 0

3 years ago

What is the equation of the line that passes through the points (4/5,1/5) and (1/2,3/2)?

Setler [38]

Answer:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$ point-slope form

$13x+3y=11$ (standard form)

Let me know if you prefer another form.

Step-by-step explanation:

The slope of a line can be found using $\frac{y_2-y_1}{x_2-x_1}$ provided you are given two points on the line.

We are.

Now you can use that formula. But I really love to just line up the points vertically then subtract them vertically then put 2nd difference over 1st difference.

(4/5 , 1/5)

-( 1/2 , 3/2)

-----------------

3/10 -13/10

2nd/1st = $\frac{\frac{-13}{10}}{\frac{3}{10}}=\frac{-13}{3}$ is our slope.

So the following is point-slope form for a linear equaiton:

$y-y_1=m(x-x_1) \text{ where } m \text{ is slope and } (x_1,y_1) \text{ is a point on the line }$

Plug in a point $(x_1,y_1)=(\frac{1}{2},\frac{3}{2}) \text{ and } m=\frac{-13}{3}$ .

This gives:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$

I'm going to distribute:

$y-\frac{3}{2}=\frac{-13}{3}x-\frac{-13}{6}$

Now I don't like these fractions so I'm going to multiply both sides by the least common multiply of 2,3, and 6 which is 6:

$6y-9=-26x+13$

Add 26x on both sides:

$26x+6y-9=13$

Add 9 on both sides:

$26x+6y=22$ This is actually standard form of a line.

It can be simplified though.

Divide both sides by 2:

$13x+3y=11$ (standard form)

7 0

3 years ago

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