Attached is the question

The polynomial p(x)=(3-2x)(x^2-5) is graphed in a coordinate plane. Which statement about the graph is correct?

satela [25.4K]

Answer:

0 = (3-2x) x (x x 2 -5)

(3-2x) x ( x x 2 - 5) = 0

(3-2x) x (2x - 5) = 0

3 - 2x = 0

2x - 5 = 0

x = 3/2

x = 5/2

x1 = 3/2 or x2 = 5/2

7 0

3 years ago

PLEASE HELP NEED ASAP

Mice21 [21]

Answer:

Side WZ=9

Step-by-step explanation:

Since he two are similar you need to make a ratio of the two parallelograms

The first tells you side FE is 2 and side EH is 3 so write it like this 2/3.

Next you need to do the same thing with the second parallelogram, so you know side XW is 6 but you don't know side WZ so you'd write this one 6/x.

You can do this since FE is similar to XW, because it is the same shape just bigger.

Next you take the two fractions adn set them equal to each other.

2 6

_ = _

3 x

Now cross multiply (2 timesx and 6 times 3)

It should look like this now

2x=18

Now all you have to do is divide by 2.

7 0

3 years ago

Read 2 more answers

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

The complement of angle a is 20° less than half the supplement of angle a. find the measure of angle a.

igor_vitrenko [27]

Answer:

∠a=40°

Step-by-step explanation:

complement of angle a=90-a

supplement of angle a=180-a

90-a=1/2(180-a)-20

multiply by 2

180-2a=180-a-40

180-180+40=-a+2a

a=40

8 0

1 year ago

Geometry

Crank

I honestly have no idea. Geometry is my worst subject

4 0

2 years ago