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andreev551 [17]
3 years ago
5

1.5(2-4h)=6hplease anwser

Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

1/4 =h

Step-by-step explanation:

1.5(2-4h)=6h

Distribute

3  -6h = 6h

Add 6h to each side

3-6h+6h = 6h+6h

3 = 12h

Divide by 12

3/12 = 12h/12

1/4 =h

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If two triangles have equal perimeters, then they could also have which of the following? Select all that apply.
Radda [10]

Answer: The answers is (B) equal areas.

Step-by-step explanation:  Given that two triangles have equal perimeters.

As shown in the attached figure, let us consider two right-angles triangles, ΔABC and ΔDEF, with sides AB = 3 cm, BC = 4 cm, AC = 5 cm, DE = 4 cm, EF = 3 cm and DF = 5 cm.

So the perimeters of both the triangles = 3 + 4 + 5 = 4 + 3 + 5 = 12 cm.

Since volume term is not valid in case of triangles, so they cannot have equal volumes. Therefore, option (A) is incorrect.

Area of ΔABC is

A_{ABC}=\dfrac{1}{2}\times AB \times BC = \dfrac{1}{2}\times 3\times 4=6~\textup{cm}^2,

and area of ΔDEF is

A_{DEF}=\dfrac{1}{2}\times DE\times EF=\dfrac{1}{2}\times 4\times 3=6~\textup{cm}^2.

Therefore, they may have equal areas and so option (B) is correct.

If the triangles have equal bases, then the heights will also be equal and both the triangles will be same. Similar is the case with equal heights. So, options (C) and (D) are incorrect.

Thus, the correct option is (B). equal areas.

4 0
3 years ago
The sum of three consecutive multiples of 3 is equal to 6 more than four times the smallest multiple. What is the largest multip
Setler79 [48]

Answer:  (a) 9

<u>Step-by-step explanation:</u>

1st multiple of 3: 1(3x)

2nd multiple of 3: 2(3x)

3rd multiple of 3: 3(3x)

Sum = 4(1st multiple of 3) + 6


1(3x) + 2(3x) + 3(3x) = 4(3x) + 6

 3x  +    6x  +    9x  =  12x  + 6

                        18x  = 12x + 6

                          6x =           6

                            x = 1


Largest (3rd) multiple is: 3(3x)

                                      = 9x

                                      = 9 · 1

                                      = 9

5 0
3 years ago
Read 2 more answers
A 6000-seat theater has tickets for sale at $28 and $40. How many tickets should be sold at each price for a sellout show to gen
irakobra [83]

Answer:

3,833 for $28

2167 for $40

Step-by-step explanation:

Let X be the number of tickets sold at the price of $24, And Y be the number of tickets sold at the price of $40.

Now,   $ 28X will be the revenue generated due to the $28 tickets

And,   $40Y will be the revenue generated due to the 40$ tickets.

Now, Total revenue generated should be $194400.

Thus ,   28X + 40Y  = 194400  -(1).

Also,

Total number of seats in theater is 6000.

So, X + Y = 6000.  -(2)

X = 6000 - Y.

Put in equation 1

We get ,    168,000 - 28Y + 40Y = 194,400

                   12Y = 26,000

                      Y = 2,166.66

Since , Y is of 40 $ so minimum tickets sold should be 2167.

X = 3,833.

4 0
3 years ago
Help??
julsineya [31]
You would use the equation 

F+V=E+2
3 0
3 years ago
Read 2 more answers
a wall is 2m at one end and 2.4m at the other end. the area of the wall is 26.4m squared. what is the length of the wall?
andrew11 [14]
Since the height is different on both ends, we can assume that the wall is a trapezoid. Knowing that, we can replace the measures we know in the formula and our onky variable is the length of the wall - we only need to isolate it. A= ((b+B)h)/2 26.4=((2+2.4)h)/2 52.8=4.4h h=12
6 0
2 years ago
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