3 years ago

Find.................

1 answer:

3 0

Its -7

use https://www.symbolab.com/solver/algebra-calculator

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dmitriy555 [2]

Answer: D (-/ 13 - -/11) those are supposed to be square root signs lol^^

Step-by-step explanation:

3 0

3 years ago

SIZIF [17.4K]

Assuming you're solving for $d(n)$ , we have by substitution

$d(n) = n d(n-1) \implies d(n-1) = (n-1) d(n-2) \\\\ ~~~~ \implies d(n) = n(n-1)d(n-2)$

$d(n) = n d(n-1) \implies d(n-2) = (n-2) d(n-3) \\\\ ~~~~ \implies d(n) = n(n-1)(n-2)d(n-3)$

$d(n) = n d(n-1) \implies d(n-3) = (n-3) d(n-4) \\\\ ~~~~ \implies d(n) = n(n-1)(n-2)(n-3) d(n-4)$

and so on. After $k$ iterations of this, we have the pattern

$d(n) = n(n-1)(n-2)\cdots(n-(k-3))(n-(k-2))(n-(k-1)) d(n-k)$

so that after $k=n-1$ iterations,

$d(n) = n(n-1)(n-2)\cdots(n-(n-3))(n-(n-2)) d(n-(n-1)) \\\\ ~~~~= n(n-1)(n-2)\cdots3\cdot2\,d(1) \\\\ ~~~~ = \boxed{n!}$

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1 year ago

Leona [35]

Answer:

Step-by-step explanation:

Answer is in the pic I promise nothing bad.

6 0

3 years ago

enot [183]

...... ....as i said,b = 17

4 0

3 years ago

7nadin3 [17]

Answer:

1<x≤8

Step-by-step explanation:

x is greater than one, but is less than or equal to 8

4 0

3 years ago