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melisa1 [442]
3 years ago
7

3(2-b) < 10-3(b-6) please help

Mathematics
2 answers:
Sonbull [250]3 years ago
7 0
3(2-b)<10-3(b-6)
6-b<5(b-6)
6-b<5b-30
Let's make "b".......2
6-(2)<5(2)-30
4<10-30
4<-20
In this case, this is a false statement. You can make "b" any number and I chose 2. I hope this helped!
musickatia [10]3 years ago
5 0
First you distribut the 3 into (2-b) 
then distribute -3 into (b-6)
to get 
6-3b<10-3b+18

then simplify

-3b+3b>10+18-6

 0>22
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What is the answer to this problem? <br><br> 2 1/3 + 3 1/3 =?
Naily [24]

Answer:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

Exact Form:

173

Decimal Form:

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Step-by-step explanation:

3 0
3 years ago
Given m &lt; TUV = 78, find m &lt; WUV
meriva

Answer:

m∠WUV = 23°

Step-by-step explanation:

m∠TUW and m∠WUV must add up to m∠TUV

Step 1: Set up equation

m∠TUW + m∠WUV = m∠TUV

8x + 7 + 4x - 1 = 78

Step 2: Solve for <em>x</em>

12x + 6 = 78

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m∠WUV = 4x - 1

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m∠WUV = 23°

7 0
3 years ago
Dylan's expenditures for each of the past six months were: March $1,248.59; April, $1,365.38; May, $1,024.30; June, $1,100.40; J
ivann1987 [24]

Answer:

The average monthly expenditure is 1,155.35 $.

Step-by-step explanation:

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average = (March+ April + May + June + July+ August)/6

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3 0
3 years ago
Read 2 more answers
Is this is right, please help
frozen [14]
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7 0
3 years ago
Read 2 more answers
What is the range of the following function: f(x)=-x^2+x^-1 if the domain is {-2, -1, 1}
postnew [5]

f(x)= -x^2 + x^-1

f(-2)= - (-2)^2 + (-2)^-1 = -4 - 1/2 = -9/2

f(-1)= - (-1)^2 + (-1)^-1 = -1 -1    =   -2

f(1) = - (1)^2 + (1)^-1 = -1 +1 = 0

The range is { -9/2, -2, 0}


8 0
3 years ago
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