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3 years ago

3(2-b) < 10-3(b-6) please help

2 answers:

7 0

3(2-b)<10-3(b-6)
6-b<5(b-6)
6-b<5b-30
Let's make "b".......2
6-(2)<5(2)-30
4<10-30
4<-20
In this case, this is a false statement. You can make "b" any number and I chose 2. I hope this helped!

musickatia [10]3 years ago

5 0

First you distribut the 3 into (2-b)
then distribute -3 into (b-6)
to get
6-3b<10-3b+18

then simplify

-3b+3b>10+18-6

0>22

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Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

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Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

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mixas84 [53]

Answer:

A) SAS

Step-by-step explanation:

The picture gives us that two sides are congruent. We can see that an <em>angle</em> is congruent as well because they share a common point at their tip.

If we look at just the area of intersection, it looks like an X. Think of the X as two lines intersecting. Each side equals 180°, and because both triangles are made up of those sides, we can conclude that the angles are congruent as well.

Hope this helps!

3 0

3 years ago

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Darya [45]

Answer:

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6 0

2 years ago

Read 2 more answers

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katovenus [111]