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3 years ago

3(2-b) < 10-3(b-6) please help

2 answers:

7 0

3(2-b)<10-3(b-6)
6-b<5(b-6)
6-b<5b-30
Let's make "b".......2
6-(2)<5(2)-30
4<10-30
4<-20
In this case, this is a false statement. You can make "b" any number and I chose 2. I hope this helped!

musickatia [10]3 years ago

5 0

First you distribut the 3 into (2-b)
then distribute -3 into (b-6)
to get
6-3b<10-3b+18

then simplify

-3b+3b>10+18-6

0>22

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I don't understand what to do because I don't understand the question

kirill [66]

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3 years ago

Unit 1: Scientific Notation Constructed Response Assignment

balu736 [363]

brainly.com/question/5027087

Let C, S and H be the diameters of cell, sand and hair

Diameter of a cell: $C=1 \cdot 10^{-5}m$

Diameter of a grain of sand: $S=2 \cdot10^{-4}m$

Part A:

$H=0.000025=2.5 \cdot 10^{-5}$ meters, because it takes 5 movements right of the decimal dot, until there is only one digit to its left.

Part B:

we are comparing $S=2 \cdot10^{-4} m$ to $C=1 \cdot10^{-5} m$ ,

$\frac{S}{C}= \frac{2 \cdot 10^{-4}}{1 \cdot 10^{-5}}=\frac{20 \cdot 10^{-5}}{1 \cdot 10^{-5}}=20$

thus S is 20 times larger than C

Part C

$1m=1 \cdot10^9nm$

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$H=2.5 \cdot 10^{-5}m=2.5 \cdot 10^{-5} \cdot 1 \cdot 10^9nm=2.5 \cdot 10^{-5+9}=2.5\cdot10^4nm$

Part D.

$1m=1\cdot 10^9nm\\\\1nm=\displaystyle{ \frac{1m}{10^9}=1\cdot 10^{-9}m}$

thus 300 nm are written in meters as follows:

$300nm= 300\cdot 1\cdot 10^{-9}m=3\cdot 10^2 \cdot 10^{-9}m=3\cdot 10^{-7}m$

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3 years ago

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Serjik [45]

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3 years ago

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Aleks04 [339]

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3 years ago

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irina [24]

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3 years ago