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3 years ago

1.simplifyyyyyyyyyyyy

Mathematics

1 answer:

VashaNatasha [74]3 years ago

5 0

Answer:

Choice A

Step-by-step explanation:

We apply the law of exponents;

$(a^{b})^{c}=a^{bc}$

$\sqrt{0.08^{12}}=(0.08^{12})^{\frac{1}{2}}$

applying the law of exponents we simply multiply 12 and 1/2 to get;

$0.08^{6}$

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How many questions did he get correct?

romanna [79]

Answer:

15 questions correct

15/20 = 75%

each 5 questions is 25 percent of the 100% so 3 x 5 = 15 = 75%

Step-by-step explanation:

4 0

3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago

15/30 = n/34 round to the nearest tenth.

avanturin [10]

The equation given in the question has to be answered to the nearest tenth. The only thing that one should be careful about is the cross multiplication part. Other than that there is no difficulty in the given problem. Now let us get down to the equation in the question.
15/30 = n/34
30 * n = 15 * 34
30n = 510
n = 510/30
= 51/3
= 17
So the value of the unknown variable "n" comes out to be 17.

6 0

3 years ago

Read 2 more answers

85% of what number is 10.2

Free_Kalibri [48]

Answer:

n = 12

Step-by-step explanation:

85%×n = 10.2

85n/100 = 10.2

85n = 1020

n = 1020 : 85

n = 12

7 0

4 years ago

A group of 625 students has a mean age of 15.8 years with a standard deviation of 0.6 years. The ages are normally distributed.

Tom [10]

16.2-15.8/0.6=0.6667. Use normalcdf() to find the percentage from -999 to 0.6777 which is 0.7476*625=467

7 0

3 years ago