Fill in the table with the output values that represent the function y=4x+8 .
1 answer:
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Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
Answer:
72 ft
Step-by-step explanation:
Here, we want to get the maximum height the ball will reach
the maximum height the ball will reach is equal to the y-coordinate of the vertex of the equation
So we need firstly, the vertex of the given quadratic equation
The vertex can be obtained by the use of plot of the graph
By doing this, we have it that the vertex is at the point (3,72)
Thus, we can conclude that the maximum height the ball can reach is 72 ft
Answer:
Step-by-step explanation:
Given that minimum is 8 and maximum equals 82
Range =
No of classes =6
Class width = 76/6 ~13
But not given whether variable is discrete or continuous.
If discrete, we have classes as
8-20, 21-33, 34-46, 47-59, 60-72, 73-85
If continuous, we have classes as
8 to <21
21 to <34
and ... ending 73-<86