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Otrada [13]
3 years ago
7

Which equation would you use to solve this problem?

Mathematics
2 answers:
const2013 [10]3 years ago
8 0
I have no idea what is is but try 4 or 1,If not you should go on cymath
mr Goodwill [35]3 years ago
6 0

Answer:cyn math


Step-by-step explanation:

Try it

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Help me with this question please
scZoUnD [109]

Step-by-step explanation:

The answer which you have chosen is <u>correct</u>.

3 0
3 years ago
The least common denominator of the rational numbers x^2-y^2/(x^2-8x+15) and y^2/15(x^2-6x+9) is
Mashutka [201]

Answer:

15(x - 5)(x - 3)²

Step-by-step explanation:

factor both denominators and see what you need to do to make them equal...

(x² - y²)/[(x - 5)(x - 3)]           y²/[15(x - 3)(x - 3)]

the first denominator has (x - 5)(x - 3)          

the second denominator has 15(x - 3)(x - 3),

the least common denominator between them would be

15(x - 5)(x -3)(x - 3)     or  15(x - 5)(x - 3)²

7 0
3 years ago
In T-ball, the distance to each successive base is 50 feet. If the distance from home plate to the pitcher’s mound is 38 feet, h
JulijaS [17]

Answer:

<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>

Step-by-step explanation:

The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.

We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

50^{2} =38^{2}+x^{2}\\x^{2}=50^{2}-38^{2}\\x=\sqrt{2500-1444}\\ x=\sqrt{1056}\\ x \approx 32.5 \ ft

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.

Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

50^{2}=32.5^{2}+y^{2}\\y^{2}=50^{2}-32.5^{2}\\y=\sqrt{2500-1056.25}\\ y =\sqrt{1443} \approx 37.99

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.

<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>

8 0
3 years ago
Which choices are real numbers? Check all that apply.
Nonamiya [84]

Answer:

Step-by-step explanation:

Exponents with fractions in them are really just radical notation in a different form. You've probably seen the square root sign.

That can be written as 

x^(1/2)

...and when you take an even root of a negative number, there is no real answer. (2 is an even number).

Looking at the answer choices here, we can see that B and D use even roots, so they will give non-real answers.

So, A and C are the answer choices to select.

5 0
3 years ago
Read 2 more answers
What is the surface area of this figure
baherus [9]

Answer:

789_278913_97/1_397/_317074

Step-by-step explanation:

gvyhfeuoyefbhbhioevfbebo no ohef. ve h hoierv wfv hirev ihoev si o w our w h. while vhio f hio

8 0
3 years ago
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